I have this string
Weiss,Emery/Ap #519-8997 Quam. Street/Hawaiian Gardens,IN - 79589|10/13/2010
how do I get the Hawaiian Gardens only?
I already tried Using some
=mid(left(A1,find("/",A1)-1),find(",",A1)+1,len(A1))
it gives me emery instead
If there are always two slashes before the string you want to extract, based on Tyler M's answer you can use this
=MID(E1,
FIND("~",SUBSTITUTE(E1,"/","~",2))+1,
FIND(",",RIGHT(E1,LEN(E1)-FIND("~",SUBSTITUTE(E1,"/","~",2))))-1
)
This substitutes the second occurence of /
with a character which normally would not occur in the address, thus making it findable.
Was your intention to also include Google Spreadsheets (looking at your title)? If so,you can use the REGEXEXTRACT()
function. For example in B1
=REGEXEXTRACT(A1,"\/([\w\s]*)\,")
In Excel you could build a UDF using this regex rule like so (as an example):
Function REGEXEXTRACT(S As String, PTRN As String) As String
'We will get the last possible match in your string...
Dim regex As Object
Set regex = CreateObject("VBScript.RegExp")
With regex
.Pattern = PTRN
.Global = True
End With
Set matches = regex.Execute(S)
For Each Match In matches
If Match.SubMatches.Count > 0 Then
For Each subMatch In Match.SubMatches
REGEXEXTRACT = subMatch
Next subMatch
End If
Next Match
End Function
Call the function in B1
like so:
=REGEXEXTRACT(A1,"\/([\w\s]*)\,")
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