How can I do this math formula in JavaScript

Question

I need to work out what is the volume of liquid left in a cylinder on its side in JavaScript, how will I do the following in code?

Answer 1

You can try something like this.I have used Math.acos and Math.pow .And rest is simple Mathematics.

Since Math.acos returns NaN if the number is not between (-1 and 1) ,so I have checked before if the acos returns NaN

 function volume(diameter, depth, length) { let R = diameter / 2; if (Math.acos((R - depth )/ R) != NaN) { let a = Math.pow(R, 2) * Math.acos((R - depth) / R) - (R - depth) * (Math.pow((2 * R * depth - Math.pow(depth, 2)), 0.5)) return a * length; } else { return "Cylinder radius can't be less than depth" } } // returns volume in meter cube // 1 meter cube =1000l console.log(volume(1.08, 0.72, 2.40)*1000,"L") 

Answer 2

You can use:

• ** operator for powers (or Math.pow )
• Math.acos for cos^(-1)
• Math.sqrt for the square root

 console.log(calculateVolumeInCylinder(1.08, 2.4, 0.72)) /** * @param {number} Dm - Cylinder diameter in meters. * @param {number} L - Cylinder length in meters. * @param {number} Dp - Depth in meters. * @returns {number} Volume in liters. */ function calculateVolumeInCylinder(Dm, L, Dp) { let R = Dm / 2, // R^2 cos^-1(RD/R) sA = R ** 2 * Math.acos((R - Dp) / R), // (RD) sB = (R - Dp), // SQRT(2RD-D^2) sC = Math.sqrt(2 * R * Dp - Dp ** 2); return (L * (sA - sB * sC)) * 1000; } 

Answer 3

Hi Shubh and Matt Major Thanks!!!! i manage to do it via the following.

 function round(d) // Returns a number rounded to 4 decimal places. { var multiplier = 10000; return Math.round(d*multiplier) / multiplier; }; function negative(n) { if(n<0) complain("Negative input"); return (n<0); } function calculate(vdiam,vlen,vdepth){ //var vdiam = 1.08; //var vlen = 2.40; //var vdepth = 0.72; var res = 0; //result //Convert inputs to numbers d = new Number(vdiam); l = new Number(vlen); h = new Number(vdepth); r = d/2; if(negative(d)) return; if(negative(l)) return; if(negative(h)) return; //make sure it's all kosher if(h>d) { console.log("Depth exceeds diameter"); return; } //calculate var segArea =r*r*Math.acos((rh)/r) - (rh)*Math.sqrt(2*r*hh*h); res = segArea*l; if(isNaN(res)) { console.log("Inputs must be positive numbers"); res = ""; return; } res = res*1000; return round(res); } alert(calculate(1.08,2.40,0.72));