I cannot insert it to my database mysql but I think I already did it the right way. is there anyone know how to solve it? or I missed something?. it actually all work. but it won't take the value from body that I put in postman
<?php
if (! isset($_POST['review'])) {
responJson(['success' => false, 'messege' => "'review' harus diisi"]);
exit;
}
if (! isset($_POST['rating'])) {
responJson(['success' => false, 'messege' => "'rating' harus diisi"]);
exit;
}
if (! isset($_POST['id_user'])) {
responJson(['success' => false, 'messege' => "'id_user' harus diisi"]);
exit;
}
if (! isset($_POST['id_movie'])) {
responJson(['success' => false, 'messege' => "'id_movie' harus diisi"]);
exit;
}
//bersihkan data
$review = mysqli_real_escape_string($connection, $_POST['review']);
$rating = mysqli_real_escape_string($connection, $_POST['rating']);
$user_id = mysqli_real_escape_string($connection, $_POST['id_user']);
$movie_id = mysqli_real_escape_string($connection, $_POST['id_movie']);
//masukkan data ke db
$query = mysqli_query($connection, 'INSERT INTO user_review (review, rating, id_user, id_movie)
values ("'. $review .'", "'. $rating .'", "'. $user_id .'", "'. $movie_id .'")');
//cek berhasil atau tidak dimasukkan db
if ($query) {
responJson(['success' => true, 'messege' => 'sukses memasukkan data']);
} else {
responJson(['success' => false, 'messege' => mysqli_error($connection)]);
}
Click raw and select json(application/json) from dropdown and add following code in body in json format
{
"review": "bagus",
"rating": "3",
"id_user": "2",
"id_movie": "3"
}
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