I wrote the following code using a complier which was configured to be suitable with c89 standard using eclipse.
#include <stdio.h>
int main(void) {
int i=0;
printf("initial value for variable i is: %d\n",i);
while (i<3)
{
if (i==1) {continue;}
printf("%d\n",i);
i++;
}
return 0;
}
The problem is that the code doesn't get excuted (No errors at all) and nothing shows in the console. When removing the following line of code if (i==1) {continue;}
everything works correctly.
When i
is 1
, it doesn't get its value changed, so it is still 1
on the next iteration, and the next, and … it takes a long time to change from 1
.
One advantage of a for
loop is that it bundles the loop controls in a single line. You'd not see the problem with for (i = 0; i < 3; i++)
as the loop; the continue
would jump to the i++
in the loop control.
You say you are using Eclipse as your IDE. That's probably why no output appears at all. Its "terminals" appear to the programs as a non-terminal, so I/O is fully buffered (rather than line buffered as is normally the case with terminal output). That in turn means that no output appears until the buffer fills, you call fflush(stdout)
, or the program does stop. It's a known issue with Eclipse. You could call setvbuf()
: add a line setvbuf(stdout, NULL, _IOLBUF, BUFSIZ);
at the start to ensure line buffering is in effect.
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