How to extract specific columns in a csv file at a particular date using shell-scripting?

Question

here is an extract from the csv file

I need to extract extract all columns with date 1/3/06 and having the 6th column 'MISSING PERSON'.

I have naively tried using GREP as such

 grep "1/3/06" SacramentocrimeJanuary2006.csv | grep "MISSING PERSON"

but dont get the deisred output

Answer 1

Could you please try following.

awk '/^1\/3\/06$/' && $6=="MISSING PERSON"'  Input_file

Change from awk to awk 'BEGIN{FS=OFS=","}.... in above code in case your Input_file is comma separated and you need output in comma separated fashion.