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SPRING Tomcat The requested resource is not available

 原文  2019-07-08 16:33:41  3   1    java/ spring/ tomcat/ model-view-controller

Question

I start Spring Mvc with a simple hello world application, but not working.

Use Eclipse editor and run on Tomcat Server.

pom.xml 

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>com.hello</groupId>
  <artifactId>SpringMavenHello</artifactId>
  <packaging>war</packaging>
  <version>0.0.1-SNAPSHOT</version>
  <name>SpringMavenHello Maven Webapp</name>
  <url>http://maven.apache.org</url>

  <dependencies>

    <dependency>
  <groupId>org.springframework</groupId>
  <artifactId>spring-webmvc</artifactId>
  <version>3.2.4.RELEASE</version>
    </dependency>

   <dependency>
      <groupId>javax.servlet</groupId>
      <artifactId>javax.servlet-api</artifactId>
      <version>3.1.0</version>
      <scope>provided</scope>
    </dependency>




    <dependency>
      <groupId>javax.servlet.jsp</groupId>
      <artifactId>jsp-api</artifactId>
      <version>2.2</version>
      <scope>provided</scope>
    </dependency>

  <dependency>
      <groupId>javax.servlet</groupId>
      <artifactId>servlet-api</artifactId>
      <version>2.4</version>
    </dependency>


  </dependencies>
  <build>
    <finalName>SpringMavenHello</finalName>
  </build>
</project>

web.xml 

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>Archetype Created Web Application</display-name>


    <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
    </servlet-mapping>



    <listener>
    <listener-class>org.springframework.web.context.ContextLoadListener</listener-class>
    </listener>

    <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
    </context-param>

    <welcome-file-list>
    <welcome-file>/WEB-INF/jsp/index.jsp</welcome-file>
    </welcome-file-list>

</web-app>

dispatcher-servlet.xml 

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://w3.org/2001/XMLSchema-instance"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-contex-4.0.xsd
http: / www.springframework.org / schema / mvc">


    <mvc:annotation-driven />
    <context:component-scan base-package="com.hello" />


    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/jsp" />

        <property name="suffix" value=".jsp" />

    </bean>

</beans>

index.jsp 

<html>
<body>
<a href="hello">click here</a>
</body>
</html>

welcome.jsp 

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<h1>Hello Spring MVC</h1>
</body>
</html>

HelloController 

package com.hello;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;

@Controller
public class HelloController {

    @RequestMapping(value="/hello")
    public String sayHello() {
        return "welcome"; // nome pagina
    }

}

When I run on the server and http://localhost:8080/SpringMavenHello I receve this error :The requested resource is not available.

Help me!! Please! Thanks!

1 answers

solution1
 0  

the spring-version in pom.xml ( <version>3.2.4.RELEASE</version> ) and the referred scheme-versions in dispatcher-servlet (for example: http://www.springframework.org/schema/context/spring-contex-4.0.xsd )should be consistent

i removed <welcome-file-list>... from web.xml

therefore i added start() -method to HelloController

other changes i made, are commented in source-code-examples

please try the following

web.xml 

<?xml version="1.0" encoding="UTF-8"?>
<web-app
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    id="WebApp_ID"
    version="3.0"
>
    <display-name>Archetype Created Web Application</display-name>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoadListener</listener-class>
    </listener>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
    </context-param>
    <!--not needed anymore -->
    <!--welcome-file-list>
        <welcome-file>/WEB-INF/jsp/index.jsp</welcome-file>
    </welcome-file-list-->
</web-app>

dispatcher-servlet.xml 

<beans
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://w3.org/2001/XMLSchema-instance"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-contex.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc.xsd"
>
    <!-- above schemaLocation for mvc edited -->
    <mvc:annotation-driven />

    <!-- .** added to also scan sub-packeges -->
    <!-- annotation-config="true" added allow annotation-based-configuration -->
    <context:component-scan
        base-package="com.hello.**"
        annotation-config="true"/>
    <bean
        id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver"
    >
        <property
            name="prefix"
            value="/WEB-INF/jsp" />
        <property
            name="suffix"
            value=".jsp" />
    </bean>
</beans>

HelloController 

package com.hello;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;

@Controller
public class HelloController {
    /**
     * the annotation {@link RequestMapping} can be shortened/replaced with
     * {@link GetMapping}
     *
     * @see {@link HelloController#start()}
     */
    // method specified
    @RequestMapping(value = "/hello", method = RequestMethod.GET)
    public String sayHello() {
        return "welcome"; // nome pagina
    }

    @GetMapping("/")
    public String start() {
        return "index"; // nome pagina
    }
}

Edit

by renaming your dispatcher-servlet.xml to spring-servlet.xml , there is no need to declare <context-param><param-name>contextConfigLocation... in web.xml

if you want to keep "your" name or follow "your" naming-conventions and it does not work, it might be an approach to declare the contextConfigLocation like this 

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        classpath*:**/dispatcher-servlet.xml
    </param-value>
</context-param>

Another Edit

could you solve your problem?

some steps are routine for me and i dont think of them

to start a "basic" dynamic web project with maven and spring, i do the following in eclipse:

  1. i create a new maven-project (not a simple project) 新的Maven项目

  2. i add maven-archetype-webapp Maven的原型Web应用程序

  3. i open project-properties, go into project facets and click on "convert to faceted form 项目方面

  4. i ensure "Dynamic Web Module", "Java" and "JavaScript" are selected, also ensure eachs version to use dont click apply and dont click apply and close; you have to click " Further configuration available " 项目方面

  5. in the following dialog i change Content directory to "src/main/webapp" 进一步的配置

  6. i stay in project properties, but i go into "deployment assembly" and click "add" 部署组装

  7. after i clicked add, i choose Java Build Path Entries in the upcoming dialiog Java构建路径条目

  8. i select Maven Dependencies in the next dialog and click finish 在此处输入图片说明

  9. as far as all of this is done, im going to change my pom and add the required dependencies

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