I need get second group in regular expression javascript

Question

I don't know how to get a second group given a string. Now I have Full Watch and Group 1(not completely) with (?:<p>)?@preview\\((.*)\\)(?:<\\/p>)?

Example strings:

@preview(example-component/example-component)
<p>@preview(example-component/example-component)</p>
@preview(example-component/example-component, title="sadad" text="asd")
@preview(example-component/example-component, title="sadad" text="asd" )

Full match:

@preview(example-component/example-component)

Or

<p>@preview(example-component/example-component)</p>

Or

@preview(example-component/example-component, title="sadad" text="asd")

Group 1:

example-component/example-component

Group 2:

title="sadad" text="asd"

Thanks

Answer 1

You could use

\(([^,)]+)(?:,\s*([^)]+))?

See a demo on regex101.com .

---

More verbose, this is

 \\( # match a "(" literally ([^,)]+) # not a comma nor a ) -> group 1 (?:,\\s* # a non-capturing group, followed by whitespaces ([^)]+) # not a ) -> group 2 )? # thw whole term is optional 

IN JavaScript :

 let strings = ['@preview(example-component/example-component)', '<p>@preview(example-component/example-component)</p>', '@preview(example-component/example-component, title="sadad" text="asd")', '@preview(example-component/example-component, title="sadad" text="asd" )']; let rx = /\\(([^,)]+)(?:,\\s*([^)]+))?/; strings.forEach(function(item) { let m = item.match(rx); if (typeof(m[2]) !== "undefined") { console.log(m[2]); } }); 

Answer 2

Your expression has only one matching group which matches everything inside the () , you just need to split it into 2 groups based on coma.

(?:<p>)?@preview\((.*?)(?:,\s*(.*?))?\)(?:<\/p>)?

I changed (.*) to (.*?)(?:,\\s*(.*?))?

(.*?) Non greedy all selector to match everything, non greedy makes it stop at the first coma it found

(?:,\\s*(.*?))? Non capturing group to capture everything after the previous group including , to mark it as optional using ?

(.*?) Second non greedy all selector captures everything after , excluding any spaces

https://regex101.com/r/c5qOFn/1