how to insert date using php into mysql query?
Question
what i'm trying to do is get date from html input, execute a query using that date. but i can't seem to figure out what is the problem, i'm doing everything right (or am i?)
Here is some code index.php
<head>
<script>
function showReport(str) {
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("report").innerHTML = this.responseText;
}
};
xmlhttp.open("GET", "/reports.php?q=" + str, true);
xmlhttp.send();
}
</script>
</head>
<body>
<p><b>Start typing a name in the input field below:</b></p>
<form>
Select Date: <input type="date" onchange="showReport(this.value)">
</form>
<p>Results: <span id="report"></span></p>
</body>
</html>
here is the ajax handler reports.php
// get the q parameter from URL
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "chaska";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$input_date=$_REQUEST['q'];
$date=date("Y-m-d",strtotime($input_date));
$sql = "SELECT `tec_sale_items`.product_name, `tec_sales`.date, sum(`tec_sale_items`.quantity) AS sum FROM `tec_sale_items` LEFT JOIN `tec_sales` ON `tec_sale_items`.sale_id = `tec_sales`.id WHERE DATE(`tec_sales`.date) = $date AS DATE group by `tec_sale_items`.product_name, DATE(`tec_sales`.date)";
$result = $conn->query($sql);
echo $date;
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "product: " . $row["product_name"]. " - Quantity: " . $row["sum"]. " ". "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
The query returns nothing. When I replace $date AS DATE by CURRENT_DATE the query executes fine but I want a specific date to work as well
3 answers
solution1
2 2019-07-23 10:12:10
The following is illegal SQL syntax for two reasons; it's missing quotes around the $date variable (which is a string), and you try to give it an alias (all you're doing is comparing two values, so aliasing makes little sense here).
WHERE DATE(`tec_sales`.date) = $date AS DATE
You should also be using a prepared statement with MySQLi, as shown below. Using a prepared statement means that you no longer need to worry about quoting your variables.
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "chaska";
// Create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$input_date = $_REQUEST['q'];
$date = date("Y-m-d",strtotime($input_date));
$sql = "SELECT `tec_sale_items`.product_name,
`tec_sales`.date,
sum(`tec_sale_items`.quantity) AS sum
FROM `tec_sale_items`
LEFT JOIN `tec_sales`
ON `tec_sale_items`.sale_id = `tec_sales`.id
WHERE DATE(`tec_sales`.date) = ?
GROUP BY `tec_sale_items`.product_name, DATE(`tec_sales`.date)";
$stmt = $conn->prepare($sql);
$stmt->bind_param("s", $date);
$stmt->execute();
$stmt->bind_result($product_name, $date, $sum);
if ($stmt->fetch()) {
do {
echo "product: ".$product_name. " - Quantity: " . $sum. " <br>";
} while ($stmt->fetch());
} else {
echo "0 results";
}
$stmt->close();
solution2
1 ACCPTED 2019-07-23 10:08:26
WHERE DATE(`tec_sales`.date) = $date
Use single quotes around date value, otherwise it is evaluated as arithmetic operation - 2019-07-23 = 2012 - 23 = 1989.
Correct condition:
WHERE DATE(`tec_sales`.date) = '$date'
There is no risk of sql injection, because input value is parsed by strtotime .
solution3
0 2019-07-23 10:08:01
what you did is right
Select Date: <input type="text" onchange="showReport(this.value)" >
but use text instead of date
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