I have this list:
my_list = [['ga:date'], ['ga:country', 'ga:date'], ['ga:country', 'ga:date']]
And try to iterate over it in order to get the values and its' positions, like so:
date 1
country 1
date 2
country 1
date 2
It should be later stored in a pandas df, values can be different, there is no fix.
Originally it was a list of dictionaries:
my_original_list = [
[{'name': 'ga:date'}],
[{'name': 'ga:country'}, {'name': 'ga:date'}],
[{'name': 'ga:country'}, {'name': 'ga:date'}]
]
# But I got the values out of it in a list:
my_list = [li['name'] for li in my_original_list]
# the result
my_list = [
['ga:date'],
['ga:country', 'ga:date'],
['ga:country', 'ga:date']
]
Cracked my mind already how to get it, would appreciate any help
Use list comprehension with enumerate
and flattening
for list of tuples:
my_list = [['ga:date'], ['ga:country', 'ga:date'], ['ga:country', 'ga:date']]
x = [(b, a) for i in my_list for (a, b) in enumerate(i, 1)]
print (x)
[('ga:date', 1), ('ga:country', 1), ('ga:date', 2), ('ga:country', 1), ('ga:date', 2)]
df = pd.DataFrame(x, columns = ['field','listIndex'])
print (df)
field listIndex
0 ga:date 1
1 ga:country 1
2 ga:date 2
3 ga:country 1
4 ga:date 2
Or if possible change position of columns:
x1 = [z for i in my_list for z in enumerate(i, 1)]
print (x1)
[(1, 'ga:date'), (1, 'ga:country'), (2, 'ga:date'), (1, 'ga:country'), (2, 'ga:date')]
df = pd.DataFrame(x1, columns = ['listIndex','field'])
print (df)
listIndex field
0 1 ga:date
1 1 ga:country
2 2 ga:date
3 1 ga:country
4 2 ga:date
Also if need remove values before :
:
my_list = [['ga:date'], ['ga:country', 'ga:date'], ['ga:country', 'ga:date']]
x = [(b.split(':')[-1], a) for i in my_list for (a, b) in enumerate(i, 1)]
print (x)
[('date', 1), ('country', 1), ('date', 2), ('country', 1), ('date', 2)]
df = pd.DataFrame(x, columns = ['field','listIndex'])
print (df)
field listIndex
0 date 1
1 country 1
2 date 2
3 country 1
4 date 2
You can use enumerate for this:
my_list = [['ga:date'], ['ga:country', 'ga:date'], ['ga:country', 'ga:date']]
for sublist in my_list:
for position, entry in enumerate(sublist):
print(entry, position + 1) # +1 to count positions starting at 1 instead of 0.
How about this?
import pandas
my_list = [['ga:date'], ['ga:country', 'ga:date'], ['ga:country', 'ga:date']]
df = pandas.DataFrame(data=[(sublist[i],i) for sublist in my_list for i in range(len(sublist))], columns=["field", "listIndex"])
REsult:
field listIndex
0 ga:date 0
1 ga:country 0
2 ga:date 1
3 ga:country 0
4 ga:date 1
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