How to reading .txt file , and adding space after specific position / index for each line in python

Question

I want to read .txt file and add space after a specific position/index for each line. please consider below example for more details.

suppose my file contains

12345 678 91011 12 1314

In the above file, the first row contains space after a specific position/index [4] , then after position/index[8], after position/index[14] and after position/index[17]

Expected output : I want every row in the file is having space after a specific position. ie for the first row, I want to add space after index [2], then add space after index [6], then add space after index[11], then add space after index [21], and so on...

123 45 6 78 91 011 12 131 4

As a reminder, I don't want to replace elements but add a new space after a specific position/index.

add space after a specific position/index for each line a text file

suppose my file contains :

12345 678 91 011 12 1314

Expected output :

123 45 6 78 91 011 12 131 4

Answer 1

Try this. Please note that this is the column position/index we are concerned with. This program adds a space between indexes 2 and 3 like you said. You can add the other indexes as you wish:

with open("C:/path-to-file/file.txt", "r") as file:
lines = file.read().split("\n")
newlines = []
for line in lines:
    line = line.rstrip()
    newline = line[:3] + ' ' + line[3:]   # Add more indexes here
    newlines.append(newline)

with open("C:/path-to-file/file.txt", "w") as newfile:    
    newfile.write("\n".join(newlines))