Return all rows that have the same id based on a value on one of the rows of a different column

Question

I would like to return all rows that have the same id on columnA based on a value on one of the rows of a different column say ColumnB. The joined table results look like the below, I would like to return all results that do not have at least one instance of the value I am looking for.

In the example below, I would like to list all organizations that have not been contacted at all which means the organizationname or id which does not have the value 'Contacted' in the ConStatus column.

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Answer 1

You can achieve this by using Subquery

SELECT * 
FROM table
WHERE OrgId NOT IN (
     SELECT DISTINCT OrgId
     FROM table
     WHERE ConStatus = 'Contacted'
)

The subquery will get all organization IDs which are contacted. These IDs will then be excluded using NOT IN to get the ones which are never contacted.

Answer 2

You can try using correlated subquery with not exists

select * from tablename a
 where not exists 
     (select 1 from tablename b where a.orgid=b.orgid and ConStatus = 'Contacted')

Answer 3

Try this one.

SELECT * 
    FROM table
    WHERE OrgId NOT IN (
         SELECT  OrgId
         FROM table
         WHERE ConStatus = 'Contacted'
    )