I need to query my database for users based on an array of emails and then execute a function for each result, I do this with eachAsync
:
mongoose.model('User')
.find({email: {$in: ['foo@bar.com', 'bar@foo.com']}})
/* -- Run side effects before continuing -- */
.cursor()
.eachAsync((doc) => {
// do stuff
});
The problem I'm having is that I need to return a 404
status if any of the users with the given emails do not exist.
I've been looking through the mongoose docs but I can't seem to find a way of running "side effects" when working with queries. Simply "resolving" the DocumentQuery
with .then
doesn't work since you can't turn it into a cursor afterwards.
How can I achieve this?
You could try implementing it as shown below. I hope it helps.
// Function using async/await
getCursor: async (_, res) => {
try {
const result = []; // To hold result of cursor
const searchArray = ['foo@bar.com', 'bar@foo.com'];
let hasError = false; // to track error when email from find isn't in the array
const cursor = await mongoose.model('User').find({ email: { $in: searchArray } }).cursor();
// NOTE: Use cursor.on('data') to read the stream of data passed
cursor.on('data', (cursorChunk) => {
// NOTE: Run your side effect before continuing
if (searchArray.indexOf(cursorChunk.email) === -1) {
hasError = true;
res.status(404).json({ message: 'Resource not found!' });
} else {
// Note: Push chunk to result array if you need it
result.push(cursorChunk);
}
});
// NOTE: listen to the cursor.on('end')
cursor.on('end', () => {
// Do stuff or return result to client
if (!hasError) {
res.status(200).json({ result, success: true });
}
});
} catch (error) {
// Do error log and/or return to client
res.status(404).json({ error, message: 'Resource not found!' });
}
}
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