Regex to Extract Last Part of URL and Before Another Character

Question

In the URLs

https://image/4x/c1/abc/5b026cdb06921e7ca5f7a24aff46512e--wedding-vendors-wedding-receptions.jpg https://image/4x/c1/abc/5b026cdb06921e7ca5f7a24aff46512e.jpg

I'm trying to capture 5b026cdb06921e7ca5f7a24aff46512e in both of these strings. The string will always happen after the last slash, it will be a random assortment of letters and numbers, it may or may not have --randomtext appended, and it will have .jpg at the end.

I currently have ([^\\/]+)$ to extract any string after the last slash, but would like to know how to capture everything before .jpg and --randomtext(if present). I will be using this in javascript.

Answer 1

You can split by / and take the last part, and then replace anything after -- or .jpg from end with empty string

 let arr = ["https://image/4x/c1/abc/5b026cdb06921e7ca5f7a24aff46512e--wedding-vendors-wedding-receptions.jpg","https://image/4x/c1/abc/5b026cdb06921e7ca5f7a24aff46512e.jpg"] let getText = (url) =>{ return url.split('/').pop().replace(/(--.*|\\.jpg)$/g,'') } arr.forEach(url=> console.log(getText(url))) 

If there are chances to have -- more than one time than instead of replacing you can simply match match(/^[a-z0-9]+/g) and take the first element from matched array

Answer 2

If what is after the last forward slash is a random assortment of letters and numbers a-z0-9, on option is to use a capturing group.

^.*\/([a-z0-9]+).*\.jpg$

In parts

• ^ Start of string
• .*\\/ Match until including the last /
• ([a-z0-9]+) Capture in group 1 matching 1+ chars az or digits 0-9
• .* Match any char except a newline 0+ times
• \\.jpg Match .jpg
• $ End of string

Regex demo

 const regex = /^.*\\/([a-z0-9]+).*\\.jpg$/; ["https://image/4x/c1/abc/5b026cdb06921e7ca5f7a24aff46512e--wedding-vendors-wedding-receptions.jpg", "https://image/4x/c1/abc/5b026cdb06921e7ca5f7a24aff46512e.jpg" ].forEach(s => console.log(s.match(regex)[1])); 

Answer 3

Use:

([^\/]*?)(?:--.*)?\.jpg$

and your desired match will be in $1

https://regex101.com/r/gZ9kSi/1