How to run C program from bash script with one or more arguments?

Question

This is my first time trying to create a bash script and I'm a bit confused.

I'm trying to run my c program from a bash script where the c program can take one or multiple arguments. If the c program takes 1 argument it will print the first n prime numbers depending on what was typed in. If it takes multiple arguments it will print the first n prime numbers of the largest integer argument and then the prime numbers between all possible ranges of the arguments. I'm having issues calling my c program with my bash script. Right now I'm just trying to have it find the largest integer and then print the first n integers:

file=$1
max=$2

shift
for arg in "$@"
do
    if [ $arg -gt $max ]; then
      max=$arg
    fi
done

for file in $path
do
    ./app "$file" "$max"
done

When I run the bash script if I type:

bash ./prime.sh ./prime 4 3 1

I should get: 2, 3, 5, 7

I did not include the c code because that's currently working.

Thanks!

Answer 1

Get rid of the for loop, just do:

"$path" "$max"

to run the program in $path with the argument $max .

I don't know what ./app is, but you don't need to run another program to execute a C program.