There is a dict
dict_example = {
'Request_1': {
'request_id' : '1',
'name' : 'Foo'
},
'Request_2': {
'request_id' : '2',
'name' : 'Bar'
},
'Request_3': {
'request_id' : '3',
'name' : 'Barbie'
}
And then I make API requests via iteration through this dict, each request is converted to a dataframe and the result stored in a list responses.
API_request = get_me_api(
for k,v in dict_example.items():
name=v['name'])
responses.append(API_request)
responses = [df1, df2, df3]
df1
age name city street
0 1 Foo LA street A
df2
age name city street
0 10 Bar NY street B
df3
age name city street
0 20 Barbi SF street C
I want to add additional column 'request_id' to each of the dataframes.
I tried to make through an iteration
for v in yt_params.values():
dict_example ['request_id'] = v['request_id']
# and just a list
request_ids = [1,2,3]
for response in responses:
for request in request_ids:
response['request_id'] = request
But it creates a column for every dataframe always with the last request_id
df1
age name city street request_id
0 1 Foo LA street A 3
df2
age name city street request_id
0 10 Bar NY street B 3
df3
age name city street request_id
0 20 Barbi SF street C 3
You probably need zip
Ex:
for response, id in zip(responses, request_ids):
response['request_id'] = id
You made a mistake in your loops. request_id
will always end up with the last entry in request_ids
. Here is an example of what is happening:
letters = ["a", "b", "c"]
numbers = [1, 2, 3]
end_product = {}
for letter in letters:
for number in numbers:
end_product[letter] = number
print(end_product)
Output:
{'a': 1}
{'a': 2}
{'a': 3} #Last iteration sets "a" to 3
{'a': 3, 'b': 1}
{'a': 3, 'b': 2}
{'a': 3, 'b': 3} # Last iteration sets "b" to 3
{'a': 3, 'b': 3, 'c': 1}
{'a': 3, 'b': 3, 'c': 2}
{'a': 3, 'b': 3, 'c': 3} # Last iteration sets "c" to 3
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.