I want to check my array for objects with matching values, if they match remove the object with the lowest index as that will be the one is "older"
I had success using this method for removing duplicate objects in the array, but when i get to specific values of those objects i'm not sure
someFunction() {
let cart = this.state.currentUser.cart
const newCartArray = cart.filter((light, index) => {
return index === cart.findIndex(obj => {
obj.use === light.use
})
})
cart = newCartArray
}
You could take a Map
and store the last object with a wanted key and get as result only the last stored objects.
var array = [{ id: 1, index: 0 }, { id: 2, index: 1 }, { id: 3, index: 2 }, { id: 2, index: 3 }, { id: 3, index: 4 }, { id: 1, index: 5 }, { id: 4, index: 6 }, { id: 5, index: 7 }], result = Array.from(array.reduce((m, o) => m.set(o.id, o), new Map).values()); console.log(result);
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If you like to keep the original order, you could check the same object reference for filtering.
var array = [{ id: 1, index: 0 }, { id: 2, index: 1 }, { id: 3, index: 2 }, { id: 2, index: 3 }, { id: 3, index: 4 }, { id: 1, index: 5 }, { id: 4, index: 6 }, { id: 5, index: 7 }], map = array.reduce((m, o) => m.set(o.id, o), new Map), result = array.filter(o => o === map.get(o.id)); console.log(result);
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let cart = this.state.currentUser.cart;
let index = cart.indexOf(light);
if( index != -1) {
cart.splice( index,1);
}
or if you need to check the.use
let cart = this.state.currentUser.cart;
for( let i =0; i < cart.length; i++) {
if( cart[i].use === light.use) {
cart.splice(i,1);
break;
}
}
You could filter out all the items that have subsequent items match the relevant property, like so:
const newCartArray = cart.filter((light, i, array) => {
return !array.slice(i + 1).some(obj => obj.use === light.use);
})
This should work:
someFunction() { let cart = this.state.currentUser.cart const newCartArray = cart.filter((light, index) => { return cart.slice(index + 1).findIndex(obj => { obj.use === light.use }) === -1; }) cart = newCartArray }
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