I want to extract the 4 digit year (2000) from a string or return None
or NaN
if its not present.
w = 'A70-11370; reprint; rolled; 2000; 26.5 x 38.5'
I tried this but I get a syntax error.
[int(i) for i in w.split(';') if i.isnumeric() else np.nan]
I'd strip the whitespace and reposition the validation check:
In[0]: [int(i.strip()) if str(i.strip()).isnumeric() else np.NaN for i in w.split(';')]
Out[0]: [nan, nan, nan, 2000, nan]
This must surely work
x=w.split('; ')
if x[3] == ' ':
print ("null")
else:
print (x[3])
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