I have two tables, one includes vehicle data & other includes fuel data as follows:
+------------+--------+
| vehicle_id | reg_no |
+------------+--------+
| 1 | ABC |
| 2 | DEF |
| 3 | GHI |
| 4 | JKA |
| 5 | LMN |
| 6 | OPQ |
+------------+--------+
+---------+------------+----------+------------+
| fuel_id | vehicle_id | fuel_qty | date |
+---------+------------+----------+------------+
| 100 | 1 | 10 | 2019-10-01 |
| 101 | 1 | 12 | 2019-10-02 |
| 102 | 2 | 20 | 2019-10-03 |
| 103 | 3 | 15 | 2019-10-03 |
| 104 | 2 | 25 | 2019-10-04 |
+---------+------------+----------+------------+
I tried to get all records of left table with relevant records of right table. Used following Query.
select("reg_no,sum(fuel_qty) as total")
->from('tbl_direct_fuel')
->join('tbl_vehicle', 'tbl_direct_fuel.vehicle=tbl_vehicle.vehicle_id', 'left')
->group_by ('reg_no')
The above code shows only the following output.
+--------+----------+
| reg_no | total |
+--------+----------+
| ABC | 22 |
| DEF | 45 |
| GHI | 15 |
+--------+----------+
But I need all the vehicles with un-fueled vehicles as follows.
+--------+----------+
| reg_no | total |
+--------+----------+
| ABC | 22 |
| DEF | 45 |
| GHI | 15 |
| JKA | 0 |
| LMN | 0 |
| OPQ | 0 |
+--------+----------+
You would to invert the tables in the left join
, so that vehicules with no fueling do appear in the resultset (as it is, your left join
allows for fueling without vehicules, which does not look like a relevant use case).
I would also recommend prefixing the column names with the table they come from to avoid ambiguity.
Finally, to return 0
(instead of null
) for the vehicules that had no fueling, you can use coalesce()
.
select("tbl_vehicle.reg_no, coalesce(sum(fuel_qty), 0) fuel_qty")
->from('tbl_vehicle')
->join('tbl_direct_fuel', 'tbl_direct_fuel.vehicle = tbl_vehicle.vehicle_id', 'left')
->group_by ('tbl_vehicle.vehicle_id')
Try:
select t1.reg_no, t2.fuel_total
from tbl_vehicle t1
left join (
select vehicle_id, sum(fuel_qty) fuel_total
from tbl_direct_fuel
group by vehicle_id
) t2 on t1.vehicle_id = t2.vehicle_id
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.