How to convert negative datetime.timedelta to positive datetime.timedelta value

Question

so I have multiple time value which I wanna subtract with each other but some of the cases I receive negative timedelta how do I convert it into positive without change the actual value

I tried to use abs() but it change the actual value

#for example:
time1=timedelta(hours=23,minutes=25,seconds=00)
time2=timedelta(hours=6,minutes=13,seconds=00)

delta_time_value = time2 -time1
print(delta_time_value) #-1 day, 13:01:00 (ANSWER)

The result which I was getting is -1 day, 13:01:00 but I want the result like this 1 day, 13:01:00 without -ve sign

Answer 1

from datetime import timedelta

time1=timedelta(hours=23,minutes=25,seconds=00)
time2=timedelta(hours=6,minutes=13,seconds=00)

delta_time_value = str(time2 - time1)

print(delta_time_value)

if delta_time_value[0] == "-":
  print(delta_time_value[1:])

This is a easy fix, not sure if it is what you are looking for.

Answer 2

time1=timedelta(hours=23,minutes=25,seconds=00)
time2=timedelta(hours=6,minutes=13,seconds=00)

print('{}'.format(time2 -time1).replace("-",""))

Simple usage of str.replace() should suffice as we are not aware which timedelta would be greater. This would replace the "-" (minus) sign only. Thanks.

Answer 3

If you just want the positive value, you can use "abs()" but you need to change the value in a float first:

time1=timedelta(hours=23,minutes=25,seconds=00)
time2=timedelta(hours=6,minutes=13,seconds=00)

delta_time_value = time2 -time1
print(delta_time_value) # OUTPUT -1 day, 13:01:00

print(delta_time_value.total_seconds()) # OUTPUT -61920.0
print(abs(delta_time_value.total_seconds())) # OUTPUT 61920.0

And if you want a string at the end, you just need to do a simple f-string with the value (in 'int' this time):

a = int(abs(delta_time_value.total_seconds()))
format = f'{a // 3600}:{(a % 3600) // 60}:{a % 60}0'
print(format) # OUTPUT 17:12:00