Printing file name and file path to a csv

Question

I am new to programming and am not sure of the best way to achieve my end goal.

I would like to create a script that will walk through a directory tree with hundreds of systematically named image files and then print the file names and file paths to a csv.

I understand how to use os.walk to list all images however I not sure how best to achieve my final output, eg should I create two lists (one with the file names and one with the file paths) or is there a better method for collecting my data for export to csv?

path = '/Users/User/Photos/'

for root, dirs, files in os.walk(path):
    for x in files:
        file_path= os.path.join(root, x)
        print(file_path)
        file_name= os.path.basename(x)
        print(file_name)

Can somebody please point me towards the best method for printing the file_name and file_path pairs to a csv?

Answer 1

You can do it like so:

import os


path = '/Users/User/Photos/'
with open('tree.csv', 'w') as fout:
    fout.write('file_name,file_path\n')
    for root, dirs, files in os.walk(path):
        for x in files:
            file_path= os.path.join(root, x)
            file_name= os.path.basename(x)
            fout.write('{},{}\n'.format(file_name, file_path))

A csv file will be created under the name tree.csv that looks like this: