Remove HTML code and output in PHP destination url

Question

I wanted to pull out html code Target URL and forgive with a variable

<a href="https://www.test.de/adtrack/3a10056f3.html" target="_blank"><img src="https://www.test.de/adtrack/3a10056f3.img" border="0" /></a>

$url = https://www.test.de/adtrack/3a10056f3.html

the $url wants to echo that too in php

Answer 1

Just echo the whole thing with your variable added in it.

$url = 'https://www.test.de/adtrack/3a10056f3.html'
echo '<a href="'.$url.'" target="_blank"><img src="https://www.test.de/adtrack/3a10056f3.img" border="0" /></a>';

or, echo it inside your html like this:

<a href="<?php echo $url; ?>" target="_blank"><img src="https://www.test.de/adtrack/3a10056f3.img" border="0" /></a>

If you do as above, remember that your file extension should be ".php" and not ".html" or else it won't work.