I have some code here to update my database based on two columns in the CSV. The CSV file would look like this:
ID Response
1 Hello1
2 Hello2
3 Hello3
In my database I have a table that also contains an id column and an extra column that matches response. The idea is this CSV file is uploaded and will populate the response that matches the ID number.
Basically this: " UPDATE tbl_data SET response = {$response} WHERE id = {$id}
"
The form that performs this action look like this:
<form method="post" name="uploadCSV" enctype="multipart/form-data">
<label>Choose CSV File</label>
<input type="file" name="csv_file" id="file" accept=".csv" />
<button type="submit" name="import" class="read-more smaller">Upload</button>
</form>
However, I don't think I've understood how to do this properly, as I get SQL errors, or the form just sits there as if nothing has happened. See code below.
if (isset($_POST["import"])) {
if($_FILES["csv_file"]["name"]){
$filename = explode(".", $_FILES["csv_file"]["name"]);
if(end($filename) == "csv"){
$handle = fopen($_FILES["csv_file"]["tmp_name"], "r");
while ($data = fgetcsv($handle)){
$id = $data[0];
$response = $data[1];
$query ="UPDATE tbl_data SET response = {$response} WHERE id = {$id}";
$update_data = mysqli_query($connection,$query);
if (!$update_data) {
$message = "There was a problem updating your CSV file. If this problem reoccurs, please contact admin";
die (mysqli_error($connection));
}
}
fclose($handle);
header("Location: upload.php?uploaded=1");
} else {
$message = "You can only upload a CSV file.";
}
} else {
$message = "Please select a CSV file.";
}
}
I have the $message to shows the message. but it doesn't show up any of the messages, and the update in the database doesn't appear to take place either.
Is there any errors that I may have overlooked in my code? Or is there a much better way to do this?
Got it working by using the following
if(isset($_POST["importcsv"])){
$file = $_FILES["csv_file"]["tmp_name"];
$handle = fopen($file,"r");
while ($row = fgetcsv($handle)) {
$id = $row[0];
$response = $row[1];
$sql = "UPDATE table SET response = ? WHERE id = ?";
$update_data_stmt = mysqli_stmt_init($connection);
if (!mysqli_stmt_prepare($update_data_stmt, $sql)){
die("Something went wrong with the upload. " . mysqli_error($connection));
} else {
mysqli_stmt_bind_param($update_data_stmt, "ss", $response, $id);
mysqli_stmt_execute($update_data_stmt);
if ($id == "ID" && $response == "Response"){
echo "";
} else {
echo "Lead <b>{$id}</b>'s response was updated to <b>{$response}</b>.</p>";
}
}
}
}
I suspect something goes wrong with your database, since you say your $message
is echoed after all of this but is empty. Assuming that your $data
contain the correct information (I would suggest var_dump()
ing to make sure), I could only imagine the statement not executing as should.
I'm not too well versed in mysqli
, however you might want to consider using PDO
to see if it works. It also protects you against potential SQL Injection attacks from the csv file:
$conn = new PDO(db_host, db_user, db_pw)
while ($data = fgetcsv($handle)) {
$id = $data[0];
$response = $data[1];
$sql = "UPDATE tbl_data SET response = :response WHERE id = :id";
$st = $conn->prepare($sql)
$st->bindValue(":response", $response, PDO::PARAM_STR)
$st->bindValue(":id", $id, PDO::PARAM_INT)
$st->execute();
//Output
print_r($st->errorInfo());
}
$conn = null;
Try this and errorInfo()
should give you sufficient logs to see what is wrong.
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