Given a dictionary and an int
value p
, I want to return the sum of its values where the key is greater than p
.
For example:
{5:3,10:5,15:7,20:9}
, when p = 18 the result is 9
{20:3,40:5,60:7,80:9}
, when p = 25 the result is 5 + 7 + 9 = 21
{10:1,20:2,30:3,40:4}
, when p = 29 the result is 3 + 4 =7
What should I do to identify the integer key and sum up the value keys and return an answer?
What about:
>>> d = {5:3,10:5,15:7,20:9}
>>> sum(v for k, v in d.items() if k > 18)
9
>>> d = {20:3,40:5,60:7,80:9}
>>> sum(v for k, v in d.items() if k > 25)
21
>>> d = {10:1,20:2,30:3,40:4}
>>> sum(v for k, v in d.items() if k > 29)
7
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