I need a solution that shows me which rows are identical but I can't find a clever solution (a solution without a bunch of complex loops). I would prefer a data.table
solution. What I want to have is a list with line numbers that have the identical entries.
An example:
library(data.table)
Data <- data.table(A = c("a", "a", "c"),
B = c("A", "A", "B"))
The first and the second line are identical. My desired output:
[[1]]
[1] 1 2
[[2]]
[1] 3
Here is something quick and dirty:
Data[, .(.I, .GRP), by = .(A, B)][, list(split(I, GRP))]$V1
Could be simplified to:
Data[, .(list(.I)), by = .(A, B)]$V1
That was my solution until sindri_baldur came up with a better solution:
Data.unique <- unique(Data)
Data.unique[, G := .I]
Data[, I := .I]
Data.full <-
merge(Data,
Data.unique,
by = c("A", "B"))
Data.full %>%
split(by = "G") %>%
map(~ .x[, I])
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