PHP 7.3 Warning: count(): Parameter must be an array or an object that implements Countable

Question

Warning: count(): Parameter must be an array or an object that implements Countable

$tags=locchuoi($request,"<span class='SeoH1'>",'</span>');
for($ll=1;$ll<count($tags)+1;$ll++)
{
    $tag_link =   $tag_link.$tags[$ll].",";
}

Answer 1

simple replace Count with !empty your problem is solved

 $tags=locchuoi($request,"<span class='SeoH1'>",'</span>'); for($ll=1;$ll<=(!empty($tags) ? count($tags) : 0);$ll++) { $tag_link = $tag_link.$tags[$ll].","; }

Answer 2

$tags=locchuoi($request,"<span class='SeoH1'>",'</span>');
for($ll=1;$ll<(!empty($tags) ? count($tags)+1 : 0);$ll++)
{
   $tag_link =   $tag_link.$tags[$ll].",";
}

Try this code, I just add some condition inside the for() , when the $tags varible is empty return 0 , if not return count($tags)+1 .

Answer 3

print_r($tags);

use this and check the output of tags. it might be null, so you are getting like this.check

 `locchuoi($request,"<span class='SeoH1'>",'</span>');` 

this function is returning the exact output which you need.