Comparison of two files using awk and print non matched records

Question

I am comparing two files file1 and file2, i need to print the updated records of file2 which am comparing in file1. i need data changes of file2 and newly added records

File1:

1|footbal|play1
2|cricket|play2
3|tennis|play3
5|golf|play5

File2:

1|footbal|play1
2|cricket|play2
3|tennis|play3
4|soccer|play4
5|golf|play6

output file:

4|soccer|play4
5|golf|play6

i have tried the below solution but its not the expected output

awk -F'|' 'FNR == NR { a[$3] = $3; a[$1]=$1; next; } { if ( !($3 in a) && !($1 in a) ) { print $0; } }' file1.txt file2.txt

i have compared the column1 and column3 from both files

Answer 1

Could you please try following.

awk 'BEGIN{FS="|"}FNR==NR{a[$1,$3];next} !(($1,$3) in a)' Input_file1  Input_file2

OR a non-one liner form of solution.

awk '
BEGIN{
  FS="|"
}
FNR==NR{
  a[$1,$3]
  next
}
!(($1,$3) in a)
'  Input_file1  Input_file2

Explanation: Adding detailed explanation for above code.

awk '               ##Starting awk program from here.
BEGIN{              ##Starting BEGIN section of this program from here.
  FS="|"            ##Setting FS as pipe here as per Input_file(s).
}                   ##Closing BEGIN block for this awk code here.
FNR==NR{            ##Checking condition FNR==NR which will be TRUE when 1st Input_file named file1 is being read.
  a[$1,$3]          ##Creating an array named a with index os $1,$3 of current line.
  next              ##next will skip all further statements.
}
!(($1,$3) in a)     ##Checking condition if $1,$3 are NOT present in array a then print that line from Input_file2.
'  Input_file1  Input_file2     ##mentioning Input_file names here.

Output will be as follows.

4|soccer|play4
5|golf|play6