regex preg_replace php

Question

I have random variable like: Strip @ 489.000 Strip 1 @ 489.000 Strip 2 @ 589.000

I need output will be: only number after 'anything @ ' 489.000

so give me output: 489.000 489.000 589.000

hot to achive this use php regex?

$string = '  Strip 1 @ 489.000'; $pattern = ' /(\s\S) @ (\d+)/i'; $replacement = '$3'; echo preg_replace($pattern, $replacement, $string);

Answer 1

To get all matches, use

if (preg_match_all('/\S\s@\s+\K\d+(?:\.\d+)?/', $text, $matches)) {
    print_r($matches[0]);
}

To get the first match, use

if (preg_match('/\S\s@\s+\K\d+(?:\.\d+)?/', $text, $match)) {
    print_r($match[0]);
}

Details

• \\S - a non-whitespace char
• \\s - a whitespace
• @ - a @ char
• \\s+ - 1+ whitespaces
• \\K - match reset operator
• \\d+ - 1+ digits
• (?:\\.\\d+)? - an optional sequence of a dot and 1+ digits.

See the regex demo .