I have a column containing calendar weeks plus year as string, which was constructed in way like this
select TO_CHAR(TO_DATE('01.03.2020'),'WW/YYYY') from DUAL
which results in a string like
09/2020
Is it possible to reconstruct the date from this string? I would not care if the date is start of the week, end of the week or anything else within this week.
The WW
format code counts 7-day periods starting at 1st January so just get 1st January for your year and add the correct number of 7-day periods:
Oracle Setup :
CREATE TABLE table_name ( value ) AS
SELECT TO_CHAR( DATE '2020-03-01', 'WW/YYYY' ) FROM DUAL;
Query :
SELECT TO_DATE( SUBSTR( value, 4 ), 'YYYY' ) + ( SUBSTR( value, 1, 2 ) - 1 ) * 7
AS first_day_of_week,
TO_DATE( SUBSTR( value, 4 ), 'YYYY' ) + ( SUBSTR( value, 1, 2 ) ) * 7 - 1
AS last_day_of_week
FROM table_name
Output :
\nFIRST_DAY_OF_WEEK | LAST_DAY_OF_WEEK \n:---------------- | :--------------- \n2020-02-26 | 2020-03-03 \n
db<>fiddle here
Something like this?
with test (col) as
(select '09/2020' from dual),
-- construct the whole year with week markers
whole_year as
(select to_date(substr(col, -4), 'yyyy') + level - 1 datum,
--
to_char(to_date(substr(col, -4), 'yyyy') + level - 1, 'ww') week
from test
connect by level <= add_months(to_date(substr(col, -4), 'yyyy'), 12) -
to_date(substr(col, -4), 'yyyy')
)
select min(datum)
from whole_year
where week = '09';
The whole_year
CTE - for week 09 - looks like this:
DATUM WE
---------- --
25.02.2020 08
26.02.2020 09 --> this
27.02.2020 09
28.02.2020 09
29.02.2020 09
01.03.2020 09
02.03.2020 09
03.03.2020 09
04.03.2020 10
05.03.2020 10
06.03.2020 10
which means that query I posted above, as a result, returns
<snip>
12 select min(datum)
13 from whole_year
14 where week = '09';
MIN(DATUM)
----------
26.02.2020
SQL>
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