JQuery Slider, how to make “step” size change

Question

Is it possible to use the JQuery Slider (range slider / dual slider) to have non-linear (non consistent "step" size) values?

I want to horizontal Slider to look like:

|----|----|----|----|----|--------|--------|-------------------------|--------------------------|...
0   500  750  1000  1250 1500     2000     2500                      75000                      100000...

For example, I want to have the following JQuery code:

var values = [0, 500, 750, 1000, 1250, 1500, 2000, 2500, 75000, 100000, 150000, 200000, 250000, 300000, 350000, 400000, 500000, 1000000];
var slider = $("#price-range").slider({
    orientation: 'horizontal',
    range: true,
    min: 0,
    max: 1000000,
    values: [0, 1000000],
    slide: function(event, ui) {
            var includeLeft = event.keyCode != $.ui.keyCode.RIGHT;
            var includeRight = event.keyCode != $.ui.keyCode.LEFT;
            slider.slider('option', 'value', findNearest(includeLeft, includeRight, ui.value));
            $("#price-amount").html('$' + ui.values[0] + ' - $' + ui.values[1]);
            return false;
    },
    change: function(event, ui) { 
        getHomeListings();
    }
});
function findNearest(includeLeft, includeRight, value) {
    var nearest = null;
    var diff = null;
    for (var i = 0; i < values.length; i++) {
            if ((includeLeft && values[i] <= value) || (includeRight && values[i] >= value)) {
                    var newDiff = Math.abs(value - values[i]);
                    if (diff == null || newDiff < diff) {
                            nearest = values[i];
                            diff = newDiff;
                    }
            }
    }
    return nearest;
}

The code above is not exactly working but the snap to grid functionality doesn't work.

Answer 1

Not sure if you want the slider scale to be in proportion to your values* but if so, I provided a solution to this for someone else who asked the same question. You can find my solution here . Basically I make use of the slide event that gets triggered when you move the slider to mimic the stepping, but based off a custom array defining the steps. This way it only allows you to "step" to your predefined values, even if they're not evenly spread.

*In other words if you want your slider to look like this:

|----|----|----|----|----|----|----|
0   10   20  100  1000 2000 10000 20000

then go with one of the other solutions here, but if you want your slider to look like this (diagram not to scale):

|--|--|-------|-----------|-----------|--------------------|--------------------|
0 10 20     100         1000        2000               10000                20000

Then the solution I linked to may be more what you're after.

---

Ok, this version of the script should work with dual sliders: 好的，此版本的脚本应与双滑块一起使用：

$(function() {
    var values = [0, 500, 750, 1000, 1250, 1500, 2000, 2500, 75000, 100000, 150000, 200000, 250000, 300000, 350000, 400000, 500000, 1000000];
    var slider = $("#price-range").slider({
        orientation: 'horizontal',
        range: true,
        min: 0,
        max: 1000000,
        values: [0, 1000000],
        slide: function(event, ui) {
            var includeLeft = event.keyCode != $.ui.keyCode.RIGHT;
            var includeRight = event.keyCode != $.ui.keyCode.LEFT;
            var value = findNearest(includeLeft, includeRight, ui.value);
            if (ui.value == ui.values[0]) {
                slider.slider('values', 0, value);
            }
            else {
                slider.slider('values', 1, value);
            }
            $("#price-amount").html('$' + slider.slider('values', 0) + ' - $' + slider.slider('values', 1));
            return false;
        },
        change: function(event, ui) { 
            getHomeListings();
        }
    });
    function findNearest(includeLeft, includeRight, value) {
        var nearest = null;
        var diff = null;
        for (var i = 0; i < values.length; i++) {
            if ((includeLeft && values[i] <= value) || (includeRight && values[i] >= value)) {
                var newDiff = Math.abs(value - values[i]);
                if (diff == null || newDiff < diff) {
                    nearest = values[i];
                    diff = newDiff;
                }
            }
        }
        return nearest;
    }
});

Note that it looks a little funny down the far left end, since the jumps are so close together compared to the right hand end, but you can see its stepping as desired if you use your keyboard arrows to move the slider. Only way to get around that is to change your scale to not be quite so drastically exponential.

---

Ok, if the spacing is too exaggerated when you use the true values, you could use a set of fake values for the slider & then look up the real value this corresponds to when you need to use the real value (in a similar way to what the other solutions here suggested). 好吧，如果在使用真实值时间距过大，则可以为滑块使用一组伪值，然后查找与需要使用真实值时对应的真实值（在与此处其他解决方案建议的方式类似）。 Here's the code:

$(function() {
    var trueValues = [0, 500, 750, 1000, 1250, 1500, 2000, 2500, 75000, 100000, 150000, 200000, 250000, 300000, 350000, 400000, 500000, 1000000];
    var values =     [0,   1,   2,    3,    4,    5,    6,    7,    10,     15,     20,     25,     30,     40,     50,     60,     75,     100];
    var slider = $("#price-range").slider({
        orientation: 'horizontal',
        range: true,
        min: 0,
        max: 100,
        values: [0, 100],
        slide: function(event, ui) {
            var includeLeft = event.keyCode != $.ui.keyCode.RIGHT;
            var includeRight = event.keyCode != $.ui.keyCode.LEFT;
            var value = findNearest(includeLeft, includeRight, ui.value);
            if (ui.value == ui.values[0]) {
                slider.slider('values', 0, value);
            }
            else {
                slider.slider('values', 1, value);
            }
            $("#price-amount").html('$' + getRealValue(slider.slider('values', 0)) + ' - $' + getRealValue(slider.slider('values', 1)));
            return false;
        },
        change: function(event, ui) { 
            getHomeListings();
        }
    });
    function findNearest(includeLeft, includeRight, value) {
        var nearest = null;
        var diff = null;
        for (var i = 0; i < values.length; i++) {
            if ((includeLeft && values[i] <= value) || (includeRight && values[i] >= value)) {
                var newDiff = Math.abs(value - values[i]);
                if (diff == null || newDiff < diff) {
                    nearest = values[i];
                    diff = newDiff;
                }
            }
        }
        return nearest;
    }
    function getRealValue(sliderValue) {
        for (var i = 0; i < values.length; i++) {
            if (values[i] >= sliderValue) {
                return trueValues[i];
            }
        }
        return 0;
    }
});

You can fiddle with the numbers in the values array (which represent the slider stop points) until you get them spaced out how you want. This way you can make it feel, from the user's perspective, like it's sliding proportionally to the values, but without being as exaggerated. Obviously if your true values are dynamically created, you may need to come up with an algorithm to generate the slider values instead of statically defining them...

Answer 2

HTML:

<body>
   <p>
      Slider Value: <span id="val"></span><br/>
      Nonlinear Value: <span id="nlVal"></span><br/>
   </p>
   <div id="slider"></div>
</body>

JS:

    $(function() {
     var valMap = [0, 25,30,50,55,55,60,100];
     $("#slider").slider({
        // min: 0,
         max: valMap.length - 1,
         slide: function(event, ui) {
           $("#val").text(ui.value);
           $("#nlVal").text(valMap[ui.value]);
         }
     });
    });

Answer 3

One option for you is use a step size of one and reference an array containing your selected values. Start at 0, go up to 20, get array[value_of_slider] to get your actual value. I don't know sliders well enough to tell you whether or not there is a way to give it a custom set of values.

Answer 4

I think I can offer a better solution: The idea is to keep an array with my real values apart from the slider, then to set the step attribute always to 1 and let the slider work with the index of that array and then fetch the real value from my real data array. Hope this example Helps: http://jsfiddle.net/3B3tt/3/

Answer 5

Based on the above answer and discussion from @Seburdis, and using the names from your example:

var prices_array = [0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 150, 200, 250, 500, 1000, 1500, 2000, 2500, 5000, 10000];

function imSliding(event,ui)
{
    //update the amount by fetching the value in the value_array at index ui.value
    $('#amount').val('$' + prices_arr[ui.value] + ' - $' + prices_arr[prices_arr.length - 1]); 
}

$('#slider-interval').slider({ min:0, max:values_arr.length - 1, slide: imSliding});

Answer 6

Somebody posted this on the jQuery website. See:

http://forum.jquery.com/topic/non-linear-logarithmic-or-exponential-scale-for-slider

and

http://jsbin.com/ezema

It is exactly what yo have, but way simpler (like 1 line of code).

Answer 7

here's how i did mine. demo here - http://janpatricklara.com/web/extra/jQueryUISliderUnevenSteps.html

have an array of your desired values

var amts=[50,100,150,200,225,250,300];

have the slider increment from 0 to the length of the array, with steps of 1. output the value from the index of the array instead of using the slider's actual value.

this way the increments and steps are evenly distributed. after that you can just grab the value of the label or save it to a var.

$('#amtslider').slider({
    min:0,
    max:amts.length-1,
    step:1,
    value:0,
    change:function(event, ui){
        //alert(amts[$(this).slider("value")]);
        //alert($(this).slider("value"));
        $('#lbl_amt').val(amts[$(this).slider("value")]);
    },
    slide:function(event, ui){
        $('#lbl_amt').val(amts[$(this).slider("value")]);
    }
});

Answer 8

Here is my simple solution for a custom (non consistent "step" size) dual-slider (you can modify it to a single-slider if the idea becomes clear) my slider is named "slider-euro", the text-area is named amount-euro as you can see in the code. The idea is to have a slider from 0 to 100 and an array ("realvalues") with 101 places. The slider-value is understood as the place in that array. The only thing is that you have to reference the array when you get the slider values. Here is my Example:

    $(function() {
    var realvalues = [0, 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000, 2000, 3000, 4000, 5000, 6000, 7000, 8000, 9000, 10000, 15000, 20000, 25000, 30000, 35000, 40000, 45000, 50000, 55000, 60000, 65000, 70000, 75000, 80000, 85000, 90000, 95000, 100000, 105000, 110000, 115000, 120000, 125000, 130000, 135000, 140000, 145000, 150000, 155000, 160000, 165000, 170000, 175000, 180000, 185000, 190000, 195000, 200000, 205000, 210000, 215000, 220000, 225000, 230000, 235000, 240000, 245000, 250000, 255000, 260000, 265000, 270000, 275000, 280000, 285000, 290000, 295000, 300000, 310000, 320000, 330000, 340000, 350000, 360000, 370000, 380000, 390000, 400000, 450000, 500000, 550000, 600000, 650000, 700000, 750000, 800000, 850000, 900000, 1000000, 1500000, 2000000];

    $( "#slider-euro" ).slider({
    range: true,
    min: 0,
    max: 100,
    step: 1,
    values: [ 25, 50 ],
    slide: function( event, ui ) {
    $( "#amount-euro" ).val( realvalues[ui.values[ 0 ]] + " € - " + realvalues[ui.values[ 1 ]] + " €");
    }
    });
    $( "#amount-euro" ).val( realvalues[$( "#slider-euro" ).slider( "values", 0 )] + " € - " + realvalues[$( "#slider-euro" ).slider( "values", 1 )]+" €" );
    });

Answer 9

I had to do something similar and even though this is a late response, someone else may happen on to this thread just as I did, and find my solution useful. Here is the solution I created:

http://jsfiddle.net/YDWdu/

So apparently, postings containing links to jsfiddle "must be accompanied by code".
OK - here ya go, stackoverflow... Some lovely "code" for you.

Answer 10

if min and max value are the same, slider value don't change

change this part

        if (ui.value == ui.values[0]) {
            slider.slider('values', 0, value);
        }
        else {
            slider.slider('values', 1, value);
        }

into

        if ( ui.values[0] == ui.values[1] ) {
            slider.slider('values', 0, value);
            slider.slider('values', 1, value);
        }else{
            if (ui.value == ui.values[0]) {
                slider.slider('values', 0, value);
            }else {
                slider.slider('values', 1, value);
            }
        }

Answer 11

Just change the values.

$( "#price-range" ).slider({
        range: true,
        min: 1000,
        max: 300000000,
        /*step:1,*/
        values: [ 1000, 300000000 ],
        slide: function( event, ui ) {
            if(ui.values[0]<=100000 && ui.values[1]<=100000){
                $("#price-range").slider({step:10000});
            }else if(ui.values[0]<=300000 && ui.values[1]<=300000){
                $("#price-range").slider({step:25000});
            }else if(ui.values[0]<=1000000 && ui.values[1]<=1000000){
                $("#price-range").slider({step:50000});
            }else if(ui.values[0]<=2000000 && ui.values[1]<=2000000){
                $("#price-range").slider({step:100000});
            }else if(ui.values[0]<=5000000 && ui.values[1]<=5000000){
                $("#price-range").slider({step:250000});
            }else if(ui.values[0]<=10000000 && ui.values[1]<=10000000){
                $("#price-range").slider({step:500000});
            }else if(ui.values[0]<=20000000 && ui.values[1]<=20000000){
                $("#price-range").slider({step:1000000});
            }else if(ui.values[0]<=50000000 && ui.values[1]<=50000000){
                $("#price-range").slider({step:5000000});
            }else if(ui.values[0]<=50000000 && ui.values[1]<=50000000){
                $("#price-range").slider({step:10000000});
            }else if(ui.values[0]<=200000000 && ui.values[1]<=200000000){
                $("#price-range").slider({step:25000000});
            }else{
                $("#price-range").slider({step:100000000});
            }

            $("#mins").val( ui.values[0] );
            $("#maxs").val( ui.values[1] );

        }
    });

Answer 12

Further to @Broshi's jsfiddle above, here is the code for a custom slider with range disabled:

jQuery:

var myData = [1,2,3,4,5,6,7,8,9,10,20,30,40,50,60,70,80,90,100,200,300,400,500,600,700,800,900,1000,2000,3000,4000,5000,10000,20000,30000,50000,100000,200000,500000,1000000,20000000,30000000];
slider_config = {
        range: false,
        min: 0,
        max: myData.length - 1,
        step: 1,
        slide: function( event, ui ) {
            // Set the real value into the inputs
            console.log(ui);
            $('#value').val( myData[ ui.value ] );
        },
        create: function() {
            $(this).slider('value',0);
        }
    };

$("#slider").slider(slider_config);

HTML:

<input id="value" />
<div id="slider"></div>