I am currently using python-telegram-bot
library to make a telegram bot. My problem is I am trying to have my bot respond back when using the inline command. So when a user sends the bot @botname 'text'
, I want the to store the 'text'
as a string
and then have my bot send something back with that variable.
For some reason I can not get this to work. I tried the code below, but it doesn't work...I also posted the example from the github that works but not in the way i want.
My code
def inlinequery(update, context):
"""Handle the inline query."""
query = update.inline_query.query
text = query.message_text
print(text)
update.message.reply_text(text)
Example Code
#Sends message when @botname is used
def inlinequery(update, context):
"""Handle the inline query."""
query = update.inline_query.query
results = [
InlineQueryResultArticle(
id=uuid4(),
title="Caps",
input_message_content=InputTextMessageContent(
query.upper())),
InlineQueryResultArticle(
id=uuid4(),
title="Bold",
input_message_content=InputTextMessageContent(
"*{}*".format(escape_markdown(query)),
parse_mode=ParseMode.MARKDOWN)),
InlineQueryResultArticle(
id=uuid4(),
title="Italic",
input_message_content=InputTextMessageContent(
"_{}_".format(escape_markdown(query)),
parse_mode=ParseMode.MARKDOWN))]
update.inline_query.answer(results)
def main():
# Get the dispatcher to register handlers
dp = updater.dispatcher
dp.add_handler(InlineQueryHandler(inlinequery))
# Start the Bot
updater.start_polling()
if __name__ == '__main__':
main()
You can use the User
object of the inline query to send them a message. Keep in mind that the user has to have started a private chat with the bot before the bot can send them messages.
I modified your attempt. It should work, but i have not tested it:
def inlinequery(update, context):
"""Handle the inline query."""
query = update.inline_query
text = query.query
print(text)
query.from_user.send_message(text)
Related docs:
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.