Golang gorm URL escaped

Question

I have problem with displaying URL from database in my template. I have struct:

type Tag struct {
    gorm.Model
    URL:       string
    userID:    uint
}

when I fetch all tags and try display it

{{range $element := .}}
{{$element.URL}}
{{end}}

I get escaped url. I see before was available | unescape but this don't exist anymore. I try also with custom function to return template.URL but still dont work.

This is my try:

"unscape" : func(s string) template.URL {
    return template.URL(fmt.Sprint(s))
}

Answer 1

Need to tell template engine that url is safe.

To achieve it need to return template.HTML or template.URL .

funcMap := template.FuncMap{
  "safeHTML" : template.HTML,
  "safeURL" : template.URL,
}

And then try to call Your method in template expression

{{range $element := .}}
{{safeURL $element.URL}}
{{end}}

By manual for template package :

Typed Strings

By default, this package assumes that all pipelines produce a plain text string. It adds escaping pipeline stages necessary to correctly and safely embed that plain text string in the appropriate context.

When a data value is not plain text, you can make sure it is not over-escaped by marking it with its type.

Types HTML, JS, URL, and others from content.go can carry safe content that is exempted from escaping.

The template

Hello, {{.}}!

can be invoked with

tmpl.Execute(out, template.HTML(`<b>World</b>`))

to produce

Hello, <b>World</b>!

instead of the

Hello, <b>World<b>!

that would have been produced if {{.}} was a regular string.

Answer 2

I dont know why but I must save it in variable to it be correct I fix it like this.

                "safe": func(s string) template.URL {
                   fixedurl := template.URL(s)
                   return  fixedurl
                },