Guessing Game with functions c++

Question

I am writing a guessing game program using functions for each thing, I keep getting errors saying function isn't set so when I try to call it, it isn't working. I can't figure out what I am doing wrong. I know I have arguments for the functions that aren't being used but I cant seem to figure out where or how I should include those in the function themself.

I am fairly new to programming/c++ so please no negative comments I am just trying to get as much help as I can.

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#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int getGuess(string prompt);
string getRank(int guessCount);
bool getPlayAgain(string prompt);
void playOneGame();

int main(){

    srand(time(0));
    int number = rand() % 100 + 1;
    string prompt = getGuess();
    do(
        playOneGame();
    )while(getPlayAgain())

    return EXIT_SUCCESS;

}

int getGuess(string prompt){
    int num;
    int guessCount = 0;
    prompt = cout << "Please enter a number between 1-100: ";
    cin >> num;

    if(num > 100){
        cout << "Please enter a number between 1-100: " << endl;

    }
    if(num < 1){
        cout << "Please enter a number between 1-100: " << endl;
    }
    if(num <= 100){
        cout << "The number you guessed is: " << num << endl; 
        guessCount++;
    }

}

string getRank(int guessCount){
    switch(guessCount){
        case 1: 
        case 2:
        case 3: cout << "Lucky!" << endl;
            break;
        case 4:
        case 5: 
        case 6: cout << "Awesome";
            break;
        case 7:
        case 8:
        case 9: cout << "Good";
            break;
        case 10:
        case 11:
        case 12: cout << "Meh";
            break;
        case 13:
        case 14:
        case 15: cout <<"Poor";
            break;
        default: cout << "Pathetic";
    }

}

bool getPlayAgain(string prompt){
    bool done = false;
    int num1;
    while(!done){
        cout << "Enter 1 to play again or 2 to quit: ";
        cin >> num1;

        if(num1 == 2){
            break;
        }
        else(
            getGuess();
        )

    }


}

void playOneGame(){
    getGuess();
    getRank();
    getPlayAgain();

}

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Answer 1

No return statement in getguess() function but function signature is int return type. Getguess() accepts prompt parameter as input but not used inside the function.