How to print to the next line in a .txt file in Python

Question

'''def get_us_value(fp):
    '''Insert docstring here.'''
    print()
    print(fp.readline())
    for x in fp:
        for y in x.split():
            if y == 'States':'''

I would like to print the next line after states in order to get the number associated with United States but I am currently stuck on how to print the next line after states. This is the.txt file

United
States
91.9

Answer 1

You can use \n.

For example: if you do print(“foo \nbar”) foo is line one, bar is line two.

Look at this, it can be helpful: https://www.google.co.uk/amp/s/cmdl.netips.com/2012/09/three-ways-to-write-text-to-a-file-in-python/amp/

Answer 2

You can use the next function on the file object to obtain the next line:

for x in fp:
    if 'States' in x.split():
        print(next(fp), end='')

Answer 3

You may not pick this solution as I don't know whether you can use regex or not but you can use regex to get the matching result. I don't know what the use case actually is but assuming you only have those lines in a text file, the regex States\n(.*) should match the whole line after the keyword States .

import re

print(re.findall(r"States\n(.*)", fp.read())[0])

Output:

91.9