Google Apps Script: Create a new column in array based on value of other columns

Question

I have an array that I pulled from a google sheet. It essentially reports on the performance of my client's Instagram posts. The first column in the array gives an image url and the second column gives a video url depending on if the post was an image or a video. A truncated version of the array will look like this:

[ [ 'Media URL',
    'Video thumbnail URL',    
    'Engagement',
    'Media impressions',
    'Media reach' ],
  [ 'www.sampleimageurl.com/1',
    '',
    1328,
    23359,
    22234 ],
  [ '',
    'www.samplevideourl.com/2',
    683,
    12542,
    11743 ],
  [ 'www.sampleimageurl.com/3',
    '',
    1070,
    15232,
    11863 ]]

In this array, either the 'Media URL' will have a value in it OR the 'Video thumbnail URL' will have a value in it - there will never be a condition in which either both have a value or none of them have a value.

I need your help to figure out a way to combine the values of the 'Media URL' & 'Video thumbnail URL'. The new array would look something like this:

[ [ 'URL',
    'Engagement',
    'Media impressions',
    'Media reach' ],
  [ 'www.sampleimageurl.com/1',
    1328,
    23359,
    22234 ],
  [ 'www.samplevideourl.com/2',
    683,
    12542,
    11743 ],
  [ 'www.sampleimageurl.com/3',
    1070,
    15232,
    11863 ]]

I've been experimenting with creating an empty array var newArray = [] and filling it up using an if condition with splice but i'm getting nowhere with this approach.

for (i in data) {
    var row = data[i]
    if (row[1] === "") {
      newArray.push(row.splice(1,1))
    }
    else {
      newArray.push(row.splice(0,1))
    }

Answer 1

Assuming no other column is empty, You can use filter and map :

 const data = [ [ 'Media URL', 'Video thumbnail URL', 'Engagement', 'Media impressions', 'Media reach' ], [ 'www.sampleimageurl.com/1', '', 1328, 23359, 22234 ], [ '', 'www.samplevideourl.com/2', 683, 12542, 11743 ], [ 'www.sampleimageurl.com/3', '', 1070, 15232, 11863 ]]; data[0][0] = "URL"; data[0][1] = ""; const output = data.map(row => row.filter(col => col !=="")); console.info(output);

Answer 2

Short answer:

A.map(item => { item[0] = item[0] || item [1];  item.splice(1, 1); });
A[0][0]="URL";

Live code: https://runkit.com/embed/iixibhqj5sg0

Full code snippet:

 const A = [ [ 'Media URL', 'Video thumbnail URL', 'Engagement', 'Media impressions', 'Media reach' ], [ 'www.sampleimageurl.com/1', '', 1328, 23359, 22234 ], [ '', 'www.samplevideourl.com/2', 683, 12542, 11743 ], [ 'www.sampleimageurl.com/3', '', 1070, 15232, 11863 ]]; A.map(item => { item[0] = item[0] || item [1]; item.splice(1, 1); }); A[0][0]="URL"; console.log(A);

Answer 3

function kreatiefMetKurk(){

 var array = [ [ 'Media URL',
'Video thumbnail URL',    
'Engagement',
'Media impressions',
'Media reach' ],
  [ 'www.sampleimageurl.com/1',
'',
1328,
23359,
22234 ],
  [ '',
'www.samplevideourl.com/2',
683,
12542,
11743 ],
  [ 'www.sampleimageurl.com/3',
'',
1070,
15232,
11863 ]]; 

array.map(function(row){row[1] = (row[0]+row[1]).trim(); 
                        row.shift(); 
                        return row;})

}