How does one define a if then else expression in Isabelle?

Question

It complains to me I have a parsing error but I can't find in the manual what the right syntax is suppose to be...

  | "my_function x b (Cons3 y) = if x=y then b else (Cons3 y)"

error:

Inner syntax error⌂
Failed to parse prop

Answer 1

You need brackets:

  | "my_function x b (Cons3 y) = (if x=y then b else (Cons3 y) )"

for some reason.

Found an example and copied it from this resource:

https://isabelle.in.tum.de/doc/functions.pdf

Answer 2

In the HOL object logic, the if-then-else , case , and let constructs have as low a precedence as quantifiers, which requires additional enclosing parentheses in the context of most other operations. Please have a look at https://isabelle.in.tum.de/dist/Isabelle2019/doc/logics.pdf , page 10.