How can i use cut and sed in awk?

Question

First of all I'm new here and i want to know how can i use cut and sed in awk of any method to edit my test data for keep that data to array

This is my sample data:

isdat    pts/0        10.80.24.3       Fri Sep 20 10:20:30 2019 - Fri Sep 20 11:55:51 2019  (01:35)

normally i can choose usage_time by awk '{print $15}' it's gonna be like this
output : (01:35)

and i will cut by cut -d ':' -f1 | sed -e 's/(/ /' cut -d ':' -f1 | sed -e 's/(/ /' for hour and this for minute cut -d ':' -f2 | sed -e 's/)/ /'

But cut and sed can't use in awk how can i solve this problem

Answer 1

You don't use them. Awk is perfectly capable of handling that on its own:

$ awk '
$2~/^pts/ {                     # the grep part
    split($15,a,/:/)            # split $15 by :
    for(i in a)                 # process all parts (2)
        gsub(/[()]/,"",a[i])    # remove parentheses
    print a[1],a[2]             # output both parts
}' file

Output:

01 35

Answer 2

You have a fine answer from James. Another slight twist using the last field (eg $NF ) can be:

awk '{sub(/:/," ",$NF); print substr($NF,2,length($NF)-2)}' file

Where you simply replace the ':' with ' ' and then take the substring between (..) .

Result

Piping your input to the expression above (and removing file ) results in:

01 35

There is always more than one way to skin-the-cat with awk .

Per the comment, if you do want to limit output only to when the 2nd field begins with pts , then you can do:

awk '$2~/^pts/{sub(/:/," ",$NF); print substr($NF,2,length($NF)-2)}' file

No magic.