asp.net mvc. Sending data through Get (form) and returning success in a label?(how to send and return data to the same view)

Question

I'm struggling to learn how .net mvc works. I've been trying to make sort of a anagram checker, but before that i'm making an input and send through GET (form) to the controller, and want to check for a word if it's equal with another( ex word1 == word1). and if that's true i want to send back to the view 'success' as a string to be written in a label. So i have a question. First i know how to send data through get and so far i checked if a word is equal with something and if that's true then i redirected to index. What i don't know if how can i send that 'success' back to the same view (without ajax if possible) and to write it in a label so i input a text and if that's equal with mine then it will say success under The controller:

       {
           if ( word == "word1")
           {
               //return HttpNotFound();
               return RedirectToAction("Index");

           }
           return View();
       }

the view:

@{
    ViewBag.Title = "CheckAnagram";
    Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>CheckAnagram</h2>




@using (Html.BeginForm("CheckAnagram", "Anagrams", FormMethod.Get, new { @class = "navbar-form navbar-left" }))
{
    <div class="form-group">
        @Html.TextBox("word", null, new { @class = "form-control", @placeholder = "Check for anagrams" })
    </div>
    <button type="submit" class="btn btn-default">Submit</button>
}

i know i can send a model to view but then when i reload the page it will send it again, so i can't understand how to make this work properly, what is the normal way to do it?

Answer 1

You can use TempData to pass model data to a redirect request. You can pass simple types like string, int, Guid etc. If you want to pass a complex type object via TempData, you have can serialize your object to a string and pass that. In your scenario, you can do this:

{
 if ( word == "word1")
 { 
  TempData["myresult"] = "Word match";
  //return HttpNotFound();
  return RedirectToAction("Index");
 }
 return View();
}

And your Index method will look like:

public ActionResult Index()
{
    if (TempData["myresult"] !=null)
    {
        var myresult= TempData["myresult"];
        ViewBag.myresult=myresult;
    }
    return View();
}

And in your Index view, you can simply retrieve the ViewBag value to be displayed.