I would like to create a new timestamp column with this dataframe :
Timestamp Flag
0 2019-10-21 07:48:28.272688 end
1 2019-10-21 07:48:28.449916 end
2 2019-10-21 07:48:26.740378 begin
3 2019-10-21 07:48:26.923764 begin
4 2019-10-21 07:48:41.689466 end
5 2019-10-21 07:48:37.306045 begin
6 2019-10-21 07:58:00.774449 end
7 2019-10-21 07:57:59.223986 begin
8 2019-10-21 08:32:37.004455 end
9 2019-10-21 08:32:35.755252 begin
The principe is simple :
For each rows, if I have an end => counter +=1 else (I have an begin) => counter -=1
When counter == 0 => save the id of the timestamp in a list
So the result must be:
Timestamp Flag
0 2019-10-21 07:48:28.272688 end
2 2019-10-21 07:48:26.740378 begin
3 2019-10-21 07:48:26.923764 begin
4 2019-10-21 07:48:41.689466 end
5 2019-10-21 07:48:37.306045 begin
6 2019-10-21 07:58:00.774449 end
7 2019-10-21 07:57:59.223986 begin
8 2019-10-21 08:32:37.004455 end
9 2019-10-21 08:32:35.755252 begin
Because : First end => counter = 1 (save(first row), ct = 2, ct = 1(save), ct = 0 (save), (save) ct = 1; ct =0 (save)...
Currently I can't add the corresponding values to the IDs and maybe I forgot (a) condition(s) in my code.
My Piece of code :
counter = 0
i = 0
while i < len(df):
id_timestamp_to_save = []
if df.loc[i, 'Flag'] == 'end':
counter +=1
if counter == 1:
id_timestamp_to_save = list(range(i))
else:
counter -=1
if counter == 0:
id_timestamp_to_save = list(range(i))
df['New_Timestamp'] = df['New_Timestamp'].assign(id_timestamp_to_save)
i+=1
Help me please.
According to your logic, just replace end
with 1
and begin
with -1
, then cumsum
:
counters = df.Flag.map({'end':1,'begin':-1}).cumsum().eq(0)
df[counters | counters.shift(fill_value=True)]
Output:
Timestamp Flag
0 2019-10-21 07:48:28.272688 end
3 2019-10-21 07:48:26.923764 begin
4 2019-10-21 07:48:41.689466 end
5 2019-10-21 07:48:37.306045 begin
6 2019-10-21 07:58:00.774449 end
7 2019-10-21 07:57:59.223986 begin
8 2019-10-21 08:32:37.004455 end
9 2019-10-21 08:32:35.755252 begin
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