Filter array of objects if object contains attribute with value present in another array

Question

I have the following array of objects.

const abc = [
      {
        sku: 1,
        features: ["Slim"],
        fields: [
          { label: "Material", value: "Material1" },
          { label: "Type", value: "Type1" },
        ]
      },
      {
        sku: 2,
        features: ["Cotton"],
        fields: [
          { label: "Material", value: "Material2" },
          { label: "Type", value: "Type1" },
        ]
      },
      {
        sku: 3,
        features: ["Cotton"],
        fields: [
          { label: "Material", value: "Material3" },
          { label: "Type", value: "Type2" },
        ]
      }
    ];

I want to filter only those objects whose features and fields value are present in this

const fieldsArr = ["Material1", "Material2", "Type1", "Slim"]

Expected Output is

let output = [
      {
        sku: 1,
        features: ["Slim"],
        fields: [
          { label: "Material", value: "Material1" },
          { label: "Type", value: "Type1" },
        ]
      },
      {
        sku: 2,
        features: ["Cotton"],
        fields: [
          { label: "Material", value: "Material2" },
          { label: "Type", value: "Type1" },
        ]
      },
    ]

I solved the features part like this

abc.forEach(e => {
      if (e.features.some(v => fieldsArr.indexOf(v) !== -1)) {
        output.push(e);
      }
    });

But I'm having problem with filtering the fields part. Is there a way to filter the objects based on the above condition in an optimized way.

Answer 1

You need to iterate the nested arrays as well.

 const abc = [{ sku: 1, features: ["Slim"], fields: [{ label: "Material", value: "Material1" }, { label: "Type", value: "Type1" }] }, { sku: 2, features: ["Cotton"], fields: [{ label: "Material", value: "Material2" }, { label: "Type", value: "Type1" }] }, { sku: 3, features: ["Cotton"], fields: [{ label: "Material", value: "Material3" }, { label: "Type", value: "Type2" }] }], fieldsArr = ["Material1", "Material2", "Type1", "Slim"], result = abc.filter(({ features, fields }) => features.some(v => fieldsArr.includes(v)) || fields.some(({ value }) => fieldsArr.includes(value)) ); console.log(result);

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Answer 2

Use filter, and check each items combined values of features and fields (value) with fieldsArr.

 const abc = [ { sku: 1, features: ["Slim"], fields: [ { label: "Material", value: "Material1" }, { label: "Type", value: "Type1" } ] }, { sku: 2, features: ["Cotton"], fields: [ { label: "Material", value: "Material2" }, { label: "Type", value: "Type1" } ] }, { sku: 3, features: ["Cotton"], fields: [ { label: "Material", value: "Material3" }, { label: "Type", value: "Type2" } ] } ]; const fieldsArr = ["Material1", "Material2", "Type1", "Slim"]; const res = abc.filter(item => [...item.features, ...item.fields.map(x => x.value)].some(fea => fieldsArr.includes(fea) ) ); console.log(res); // Update: more concise using destructure const res2 = abc.filter(({features, fields}) => [...features, ...fields.map(({value}) => value)].some(fea => fieldsArr.includes(fea) ) ); console.log(res2);