How to pass image value from variable in statement to another PHP file
Question
Hey so i`m trying to pass value from my PHP file where i pull the data from the database to another PHP file to an tag i have tried to display my images on the same file where i do my query and it does work but i need it in another file. thanks
if($image!="")
{
$res = mysqli_query($link,"SELECT * FROM lug_num WHERE lug_id= $image");
$array = array();
?><br><br><div id = img_lug><?php
while($row=mysqli_fetch_array($res))
{
global $img;
$img = $row["image"];
//echo $img;
?><img src="<?php echo $img; ?>" width='200' height='200' /><?php
}
?></div><?php
This is my file where i fetch and can display images and i need the $img variable in another file
<?php
include ("ajax.php");
echo $img;
?><img src="<?php include("ajax.php"); echo $img; ?>" width='200' height='200' /><?php
?>
this is me trying to include the variable in the other file but no success. before you say something about the include php file i know it`s twice i was desperate and was trying different things.
Thanks
Here is the whole file of the ajax.php
<?php
$link=mysqli_connect("localhost","root","123456");
mysqli_select_db($link,"demo");
error_reporting(0);
$make =$_GET["make"];
$model = $_GET["model"];
$year = $_GET["year"];
$oem = $_GET["oem_number"];
$lug = $_GET["lug_number"];
$image = $_GET["lug_number"];
if($make!="")
{
$res = mysqli_query($link,"SELECT * FROM models WHERE make_id= $make");
echo "<select id='modeldd' onchange='change_model()'>";
echo "<option selected = '' disabled=''>";echo "Select Model";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[model_id]'>"; echo $row["model"]; echo "</option>";
}
echo "</select>";
}
if($model!="")
{
$res = mysqli_query($link,"SELECT * FROM year WHERE model_id= $model");
echo "<select id='yeardd' onchange='change_year()'>";
echo "<option selected = '' disabled=''>";echo "Select Year";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[year_id]'>"; echo $row["year"]; echo "</option>";
}
echo "</select>";
}
if($year!="")
{
$res = mysqli_query($link,"SELECT * FROM oem WHERE year_id= $year");
echo "<select id='oemdd' onchange='change_oem()'>";
echo "<option selected = '' disabled=''>";echo "Select OEM number";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[oem_id]'>"; echo $row["oem_number"]; echo "</option>";
}
echo "</select>";
}
if($oem!="")
{
$res = mysqli_query($link,"SELECT * FROM lug_num WHERE oem_id= $oem");
echo "<select id='lugdd' onchange='change_lug()'>";
echo "<option selected = '' disabled=''>";echo "Select lug number";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[lug_id]'>"; echo $row["lug_number"]; echo "</option>";
}
echo "</select>";
}
if($lug!="")
{
$res = mysqli_query($link,"SELECT * FROM fix_type WHERE lug_id= $lug");
echo "<select>";
echo "<option selected = '' disabled=''>";echo "Select fix type";echo "</option>";
while($row=mysqli_fetch_array($res))
{
$test = $row["fix_name"];
echo "<option value = '$row[fix_id]'>"; echo $row["fix_name"]; echo "</option>";
}
echo "</select>";
}
$img = array();
if($image!="")
{
$res = mysqli_query($link,"SELECT * FROM lug_num WHERE lug_id= $image");
$array = array();
?><br><br><div id = img_lug><?php
while($row=mysqli_fetch_array($res))
{
array_push($img, $row["image"]);
//echo $img;
?><img src="<?php echo $img; ?>" width='200' height='200' /><?php
}
?></div><?php
}
?>
and the index.php
<?php
$link=mysqli_connect("localhost","root","123456");
mysqli_select_db($link,"demo");
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<form name="form1" action="" method="post">
<table>
<tr>
<td>Select Make</td>
<td><select id="makedd" onchange="change_make()">
<option>Select</option>
<?php
$res = mysqli_query($link,"SELECT * FROM `manufacturer`");
while($row=mysqli_fetch_array($res))
{
?>
<option value="<?php echo $row["make_id"];?>"><?php echo $row["make"] ?></option>
<?php
}
?>
</select></td>
</tr>
<tr>
<td>Select Model</td>
<td>
<div id="model">
<select>
<<option selected="" disabled="">Select Manufacturer</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Select Year</td>
<td>
<div id="year">
<select>
<option>Select Year</option>
</select>
</div>
</td>
</tr>
</tr>
<tr>
<td>Select OEM Number</td>
<td>
<div id="oem">
<select>
<option>Select OEM Number</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Select lug Number</td>
<td>
<div id="lug">
<select>
<option>Select Lug Number</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Select Fix type</td>
<td>
<div id="fix" >
<select>
<option>Select Fix type</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Image from lug</td>
<td><div id="image">
</div>
</td>
</tr>
</table>
<?php
include "ajax.php";
?><img src="<?php include "ajax.php"; echo $images; ?>" width='200' height='200' /><?php
?>
</form>
<script type="text/javascript">
function change_make(){
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?make="+document.getElementById("makedd").value,false);
xmlhttp.send(null);
document.getElementById("model").innerHTML=xmlhttp.responseText;
}
function change_model() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?model="+document.getElementById("modeldd").value,false);
xmlhttp.send(null);
document.getElementById("year").innerHTML=xmlhttp.responseText;
}
function change_year() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?year="+document.getElementById("yeardd").value,false);
xmlhttp.send(null);
document.getElementById("oem").innerHTML=xmlhttp.responseText;
}
function change_oem() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?oem_number="+document.getElementById("oemdd").value,false);
xmlhttp.send(null);
document.getElementById("lug").innerHTML=xmlhttp.responseText;
}
function change_lug() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?lug_number="+document.getElementById("lugdd").value,false);
xmlhttp.send(null);
document.getElementById("fix").innerHTML=xmlhttp.responseText;
}
</script>
</body>
</html>
Update so i tried with session it did not work said that i have too many sessions i tried with function same deal did not wanna work is there any way that could be done with script? Thanks
2 answers
solution1
1 ACCPTED 2020-03-19 14:07:11
ajax.php
<?php
$link=mysqli_connect("localhost","root","123456");
mysqli_select_db($link,"demo");
error_reporting(0);
$make =$_GET["make"];
$model = $_GET["model"];
$year = $_GET["year"];
$oem = $_GET["oem_number"];
$lug = $_GET["lug_number"];
$image = $_GET["lug_number"];
if($make!="")
{
$res = mysqli_query($link,"SELECT * FROM models WHERE make_id= $make");
echo "<select id='modeldd' onchange='change_model()'>";
echo "<option selected = '' disabled=''>";echo "Select Model";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[model_id]'>"; echo $row["model"]; echo "</option>";
}
echo "</select>";
}
if($model!="")
{
$res = mysqli_query($link,"SELECT * FROM year WHERE model_id= $model");
echo "<select id='yeardd' onchange='change_year()'>";
echo "<option selected = '' disabled=''>";echo "Select Year";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[year_id]'>"; echo $row["year"]; echo "</option>";
}
echo "</select>";
}
if($year!="")
{
$res = mysqli_query($link,"SELECT * FROM oem WHERE year_id= $year");
echo "<select id='oemdd' onchange='change_oem()'>";
echo "<option selected = '' disabled=''>";echo "Select OEM number";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[oem_id]'>"; echo $row["oem_number"]; echo "</option>";
}
echo "</select>";
}
if($oem!="")
{
$res = mysqli_query($link,"SELECT * FROM lug_num WHERE oem_id= $oem");
echo "<select id='lugdd' onchange='change_lug()'>";
echo "<option selected = '' disabled=''>";echo "Select lug number";echo "</option>";
while($row=mysqli_fetch_array($res))
{
echo "<option value = '$row[lug_id]'>"; echo $row["lug_number"]; echo "</option>";
}
echo "</select>";
}
if($lug!="")
{
$res = mysqli_query($link,"SELECT * FROM fix_type WHERE lug_id= $lug");
echo "<select>";
echo "<option selected = '' disabled=''>";echo "Select fix type";echo "</option>";
while($row=mysqli_fetch_array($res))
{
$test = $row["fix_name"];
echo "<option value = '$row[fix_id]'>"; echo $row["fix_name"]; echo "</option>";
}
echo "</select>";
}
$img = ""
if($image!="")
{
$res = mysqli_query($link,"SELECT * FROM lug_num WHERE lug_id= $image");
$array = array();
?><br><br><div id = img_lug><?php
while($row=mysqli_fetch_array($res))
{
$img = $row["image"];
//echo $img;
?><img src="<?php echo $img; ?>" width='200' height='200' /><?php
}
?></div>
<?php } ?>
index.php
<?php
$link=mysqli_connect("localhost","root","123456");
mysqli_select_db($link,"demo");
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<form name="form1" action="" method="post">
<table>
<tr>
<td>Select Make</td>
<td><select id="makedd" onchange="change_make()">
<option>Select</option>
<?php
$res = mysqli_query($link,"SELECT * FROM `manufacturer`");
while($row=mysqli_fetch_array($res))
{
?>
<option value="<?php echo $row["make_id"];?>"><?php echo $row["make"] ?></option>
<?php
}
?>
</select></td>
</tr>
<tr>
<td>Select Model</td>
<td>
<div id="model">
<select>
<<option selected="" disabled="">Select Manufacturer</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Select Year</td>
<td>
<div id="year">
<select>
<option>Select Year</option>
</select>
</div>
</td>
</tr>
</tr>
<tr>
<td>Select OEM Number</td>
<td>
<div id="oem">
<select>
<option>Select OEM Number</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Select lug Number</td>
<td>
<div id="lug">
<select>
<option>Select Lug Number</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Select Fix type</td>
<td>
<div id="fix" >
<select>
<option>Select Fix type</option>
</select>
</div>
</td>
</tr>
<tr>
<td>Image from lug</td>
<td><div id="image">
</div>
</td>
</tr>
</table>
<?php
include "ajax.php";
?><img src="<?php include "ajax.php"; echo $img; ?>" width='200' height='200' /><?php
?>
</form>
<script type="text/javascript">
function change_make(){
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?make="+document.getElementById("makedd").value,false);
xmlhttp.send(null);
document.getElementById("model").innerHTML=xmlhttp.responseText;
}
function change_model() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?model="+document.getElementById("modeldd").value,false);
xmlhttp.send(null);
document.getElementById("year").innerHTML=xmlhttp.responseText;
}
function change_year() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?year="+document.getElementById("yeardd").value,false);
xmlhttp.send(null);
document.getElementById("oem").innerHTML=xmlhttp.responseText;
}
function change_oem() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?oem_number="+document.getElementById("oemdd").value,false);
xmlhttp.send(null);
document.getElementById("lug").innerHTML=xmlhttp.responseText;
}
function change_lug() {
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","ajax.php?lug_number="+document.getElementById("lugdd").value,false);
xmlhttp.send(null);
document.getElementById("fix").innerHTML=xmlhttp.responseText;
}
</script>
</body>
</html>
solution2
0 2020-03-19 14:37:13
The way that you trying is wrong. Look, your $image variable can be global but your loop is not global. It will give you the last value of loop.
1.Change $img variable to local.
2.Then create a new global variable. And give it the values like this.
global $global_images;
$global_images.= "@".$row["image"]; // @ is just a separator.
3.Now on the other page (where you want), you have to create basic loop again, like this
include "2.php";
$get_images=explode('@', $global_image); //We can choose one by one the images with @ and explode function
//The loop
foreach ($get_images as $show){?>
<img src="<?php echo $show; ?>" width='200' height='200'>
<?php } ?>
As I understand it, this is exactly what you want. Now you can customize it on demand.
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