Get `val` of property from array of objects inside array of objects based on other property of the object

Question

var arr = [{req: [{type: 'high', val: 1},{type: 'low', val: 2}], other: [{random: 123}]}, {req: [{type: 'cool', val: 1},{type: 'med', val: 3}], other: [{random: 456}]}]

how write function using array functions to get value of val which is 3 from above array of objects from inside array of objects where type is med

expected result

var result = 3;

I tried to use reduce function of array

let getRequirementArray = (req, vol) =>
  req.reduce((currentVal, obj) => {
    return obj.type === vol ? obj.val + currentVal : currentVal;
  }, 0);

let getFinalOutput = (arr, vol) =>
  arr.reduce((currentVal, obj) => {
    let { req } = obj;
    let val= getRequirementArray(req, vol);
    return val + currentVal;
  }, 0);
var result = getFinalOutput(arr, 'med');

But I am expecting a little smaller function

Answer 1

You can aggregate the array into a single array of objects and then find the object with type equal to med

 var arr = [{req: [{type: 'high', val: 1},{type: 'low', val: 2}], other: [{random: 123}]}, {req: [{type: 'cool', val: 1},{type: 'med', val: 3}], other: [{random: 456}]}] var mix = [].concat(...arr.map(t => t.req)); var obj = mix.find(x => x.type === 'med'); console.log(obj.val);

Answer 2

You can use every function of Arrays and return false when you got the first value

 var value,arr = [{req: [{type: 'high', val: 1},{type: 'low', val: 2}], other: [{random: 123}]}, {req: [{type: 'cool', val: 1},{type: 'med', val: 3}], other: [{random: 456}]}] arr.every(outerObject => {let desObj = outerObject.req.find(obj => obj.type == "med");if (desObj){value=desObj.val;return false;}return true; }); console.log(value);