Simple JavaScript Regex that contains both square brackets

Question

I'm trying to write a Regex of the form: najfo359f+-q3f#~[+0asa123123]a'/.df;ekfm345

Any character including numbers 0 or more times,

1 OPENING SQUARE BRACKET,

Any character including numbers 0 or more times,

A NUMBER,

1 CLOSING SQUARE BRACKET,

and any character including numbers 0 or more times,

This is what I have so far:

 /.*[.*0*/d+].*/

But I can't match the simple [2245] and when I try to escape \ the opening square bracket my code doesn't execute.

What am I missing?

Answer 1

A few observations:

1. The 0 in the middle of your regex seems a bit arbitrary and doesn't appear to be considered in any of your criteria.
2. Unsure of why you're including a /d , maybe you meant \d ? A backslash \ is used to indicate escape sequences.

You're looking for something more akin to:

/.*\[.*\d+\].*/

Regex101

In context with Javascript:

 const pattern = /.*\[.*\d+\].*/; console.log(pattern.test("najfo359f+-q3f#~[+0asa123123]a'/.df;ekfm345")); console.log(pattern.test("[2245]"));