How to display 2 values in a textbox?

Question

I am trying to display two random generated numbers in a text-box using visual studio.

This is what I have so far...

int RandomNumber(int min = 0, int max = 100)
            {
                Random random = new Random();
                return random.Next(min, max);
            }
            int RandomNumber2(int min = 0, int max = 100)
            {
                Random random = new Random();
                return random.Next(min, max);
            }
            txtQuestion.Enabled = true;

        string num1 = Convert.ToString(RandomNumber());
        string num2 = Convert.ToString(RandomNumber2());

        txtQuestion.Text = ("{0} + {1} = ?", num1, num2);

However, the last line comes up with the error " cannot implicitly convert type '(string, string num1, string num2)' to 'string' "

How am I supposed to output these randomly generated numbers in the textbox?

Hi below is the edited code that works to how I needed it. Thanks for all the help:)

Random random1 = new Random();

I called the above function globally so I can refer to it every time I need a new random number. And below is how I used it in my function to call for two different random numbers and display them in a text-box.

            int randomNumber1 = random1.Next(0, 10);
        int randomNumber2 = random1.Next(0, 10);

        string num1 = Convert.ToString(randomNumber1);
        string num2 = Convert.ToString(randomNumber2);

        txtQuestion.Text = string.Format ("{0} + {1} = ?", num1, num2);

Answer 1

As @John said, you are using a ValueTuple. You can learn more about ValueTuple here or on the msdn. But the link I gave shows almost the same code as you wrote.

What you want to do is either to use string.Format:

txtQuestion.Text = string.Format("{0} + {1} = ?", num1, num2);

Or more concise with string interpolation:

txtQuestion.Text = $"{num1} + {num2} = ?";

And show the answer like this:

Random random = new Random();
int nextRandom() => random.Next(0, 100);
int num1 = nextRandom();
int num2 = nextRandom();
txtQuestion.Text = $"{num1} + {num2} = {num1 + num2}";
// If you have a method that computes the result you can also call it inside
txtQuestion.Text = $"{num1} + {num2} = {SomeFunction(num1, num2)}";

To fix your random issue, you must create a random instance only once.

class MyClass
{
    // Use the same instance of Random.
    private Random _random = new Random();

    public int RandomNumber()
    {
        return _random.Next(0, 100);
    }

    public void DisplayText()
    {
        int num1 = RandomNumber();
        int num2 = RandomNumber();
        txtQuestion.Text = $"{num1} + {num2} = {num1 + num2}";
    }
}