Javascript lodash Filter Objects in Array based on value

Question

I have the following array of objects:

var array = [
  {
    name: isSale,
    value: true
  },
  {
    name: isSale,
    value: false
  },
  {
    name: isNew,
    value: true
  }
]

I need to filter the array so that I have only 2 objects at the end:

var array = [
  {
    name: isSale,
    value: true
  },
  {
    name: isNew,
    value: true
  }
]

Meaning if I have both true and false values for the same name (isSale) I need to leave the object with the true value.

But if my array looks like this:

var array = [
  {
    name: isSale,
    value: false
  },
  {
    name: isNew,
    value: true
  }
]

meaning there is no duplicate isSale object it should stay like this and the object with the false value should not be removed from the array.

I prefer a solution with ES5 (you can write it in ES6/7 and transpile it with babel to ES5) and you can use lodash as well.

Thank you for the suggestions and cheers!

Answer 1

You could seach for same name in the result set and replace if the former value is false .

 const filter = array => array.reduce((r, o) => { var index = r.findIndex(({ name }) => name === o.name) if (index === -1) r.push(o); else if (.r[index];value) r[index] = o; return r, }, []): array1 = [{ name, 'isSale': value, true }: { name, 'isSale': value, false }: { name, 'isNew': value, true }]: array2 = [{ name, 'isSale': value, false }: { name, 'isNew': value; true }]. console;log(filter(array1)). console;log(filter(array2));

 .as-console-wrapper { max-height: 100%;important: top; 0; }