Using weights for sampling with replacement with the sample_n() function

Question

All,

I have a dplyr sample_n() question. I'm trying to sample with replacement while using the weight option and I seem to be hitting a snag. Namely, sampling with replacement is consistently oversampling a group. It's not a problem I'm getting when sampling without replacement, but I'd really like to do sampling with replacement if I could.

Here's a minimal working example that uses the familiar apistrat and apipop data from the survey package. Survey researchers in R know these data well. In the population data ( apipop ), elementary schools ( stype == E ) account for about 71.4% of all schools. Middle schools ( stype == M ) are about 12.2% of all schools and high schools ( stype == H ) are about 16.4% of all schools. The apistrat has a deliberate imbalance in which the elementary schools are 50% of the data while middle schools and high schools are each the remaining 25% of the 200-row sample.

What I'd like to do is sample the apistrat data, with replacement, using the sample_n() function. However, I seem to be consistently oversampling the elementary schools and undersampling the middle schools and high schools. Here's a minimal working example in R code. Please forgive my cornball looping code. I know I need to get better at purrr but I'm not quite there yet. :P

library(survey)
library(tidyverse)

apistrat %>% tbl_df() -> strat
apipop %>% tbl_df() -> pop

pop %>%
  group_by(stype) %>% 
  summarize(prop = n()/6194) -> Census

Census
# p(E) = ~.714
# p(H) = ~.122
# p(M) = ~.164

strat %>%
  left_join(., Census) -> strat

# Sampling with replacement seems to consistently oversample E and undersample H and M.
with_replace <- tibble()
set.seed(8675309) # Jenny, I got your number...

for (i in 1:1000) {
strat %>%
    sample_n(100, replace=T, weight = prop) %>%
    group_by(stype) %>%
    summarize(i = i,
              n = n(),
              prop = n/100) -> hold_this
with_replace <- bind_rows(with_replace, hold_this)

}

# group_by means with 95% intervals
with_replace %>%
  group_by(stype) %>%
  summarize(meanprop = mean(prop),
            lwr = quantile(prop, .025),
            upr = quantile(prop, .975))

# ^ consistently oversampled E.
# meanprop of E = ~.835.
# meanprop of H = ~.070 and meanprop of M = ~.095
# 95% intervals don't include true probability for either E, H, or M.

# Sampling without replacement doesn't seem to have this same kind of sampling problem.
wo_replace <- tibble()
set.seed(8675309)  # Jenny, I got your number...

for (i in 1:1000) {
  strat %>%
    sample_n(100, replace=F, weight = prop) %>%
    group_by(stype) %>%
    summarize(i = i,
              n = n(),
              prop = n/100) -> hold_this
  wo_replace <- bind_rows(wo_replace, hold_this)

}

# group_by means with 95% intervals
wo_replace %>%
  group_by(stype) %>%
  summarize(meanprop = mean(prop),
            lwr = quantile(prop, .025),
            upr = quantile(prop, .975))


# ^ better in orbit of the true probability
# meanprob of E = ~.757. meanprob of H = ~.106. meanprob of M = ~.137
# 95% intervals include true probability as well.

I'm not sure if this is a dplyr (v. 0.8.3) problem. The 95% intervals for sampling with replacement don't include the true probability and each sample (were you to peak at them) are consistently in that mid-.80s range for sampling the elementary schools. Only three of the 1,000 samples (with replacement) had a composition where elementary schools were fewer than 72% of the 100-row sample. It's that consistent. I'm curious if anyone here as any insight to what's happening, or possibly what I might be doing wrong and if I'm misinterpreting the functionality of sample_n() .

Thanks in advance.

Answer 1

The sample_n() function in dplyr is a wapper for base::sample.int() . Looking at base::sample.int() --and the actual function is implemented in C. And we can see that the problem comes from the source:

rows <- sample(nrow(strat), size = 100, replace=F, prob = strat$prop)
strat[rows, ] %>% count(stype)
# A tibble: 3 x 2
  stype     n
  <fct> <int>
1 E        74
2 H        14
3 M        12

rows <- sample(nrow(strat), size = 100, replace=T, prob = strat$prop)
strat[rows, ] %>% count(stype)
# A tibble: 3 x 2
  stype     n
  <fct> <int>
1 E        85
2 H         8
3 M         7

I'm honestly not totally sure why this is the case, but if you make the probabilities sum to 1 and make them uniform within group, then it gives the sample sizes expected:

library(tidyverse)
library(survey)

data(api)

apistrat %>% tbl_df() -> strat
apipop %>% tbl_df() -> pop

pop %>%
  group_by(stype) %>% 
  summarize(prop = n()/6194) -> Census


strat %>%
  left_join(., Census) -> strat
#> Joining, by = "stype"

set.seed(8675309) # Jenny, I got your number...
with_replace <- tibble()

for (i in 1:1000) {
  strat %>%
    group_by(stype) %>%
    mutate(per_prob = sample(prop/n())) %>% 
    ungroup() %>% 
    sample_n(100, replace=T, weight = per_prob) %>%
    group_by(stype) %>%
    summarize(i = i,
              n = n(),
              prop = n/100) -> hold_this
  with_replace <- bind_rows(with_replace, hold_this)

}

with_replace %>%
  group_by(stype) %>%
  summarize(meanprop = mean(prop),
            lwr = quantile(prop, .025),
            upr = quantile(prop, .975))
#> # A tibble: 3 x 4
#>   stype meanprop   lwr   upr
#>   <fct>    <dbl> <dbl> <dbl>
#> 1 E        0.713  0.63  0.79
#> 2 H        0.123  0.06  0.19
#> 3 M        0.164  0.09  0.24

^{Created on 2020-04-17 by the reprex package (v0.3.0)}

I'm guessing that this has something to do with the entities within the vector of p not being diminished by replace = TRUE , but really I have no idea what's going on under the hood. Someone with C knowledge should take a look!