I get the following error when I try to open a new page from the menu. in PHP7.4
I think that mssql_num_rows() for checking if the number of rows is greater than zero will solve the problem but I can't implement it in this code due to my poor knowledge with PHP and my lack of time.
public function getCompany()
{
/** @var $Params array */
$Params = $this->getURLParams();
$sql = sprintf("
SELECT CompanyName.ID
FROM CompanyName, SiteTree
WHERE CompanyName.Slug = '%s' and CompanyName.CompanyPageID = SiteTree.ID and SiteTree.URLSegment = '%s'
", $Params['Action'], $Params['URLSegment']);
/** @var $row array */
$row = DB::query($sql)->current();
/** @var $Company CompanyName */
$Company = DataObject::get_by_id(CompanyName::class, intval($row['ID']));
if (!$Company instanceof CompanyName) {
return false;
}
/** @var $CompanyPage CompanyPage */
$CompanyPage = $Company->CompanyPage();
if ($CompanyPage->getField('URLSegment') != $Params['URLSegment'])
{
return false;
}
return $Company;
}
Any idea how to solve this problem?
Thank you.
Solved, I changed:
$Company = DataObject::get_by_id(CompanyName::class, intval($row['ID']));
to
$Company = DataObject::get_by_id(CompanyName::class, intval($row['ID']??='default value'));
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