typescript / javascript array.filter() with multiple conditions not returning expected values

Question

I have cell definition with two properties:

class Cell {
  x: number;
  y: number;

  constructor(x: number, y: number) {
    this.x = x;
    this.y = y;
  }
}

lets create new array who contains some cells:

let x : Cell[]=[new Cell(5,5),new Cell(5,9), new Cell(5,56)]

I would like to filter one cell (if exists in array, and return rest of the array):

x= x.filter(c=>(c.x!==5 && c.y!==5)

I`m expecting to get back array with 2 last cells, but it returns none of cells. It works fine if just one condition is used. Any solutions for multiple conditions?

Answer 1

You have the logic wrong. In order to match with Cell(5,5) you use

c => c.x === 5 && c.y === 5

But to filter it out you use the negative:

c => !(c.x === 5 && c.y === 5)

which is the same as

c => c.x !== 5 || c.y !== 5

Answer 2

Your Question was a little confusing I'm writing this based on my assumption.

You want to return the last two cells but that condition was contradictory as the last cells are having 5 as the value of x so you can check this condition to return the last two cells.

x= x.filter(c=>(c.x == 5 && c.y > 5))

In the second condition, I used greater than the operator to get the desired results.

If you found this incorrect let me know I will help.