Attaching Azure Blob from stream to SendGrid email

Question

I'm attempting to send an Azure Blob as an attachment via SendGrid. My first step is to download the blob as such:

download_client=BlobClient.from_connection_string(
        conn_str=az_str, 
        container_name=container_name, 
        blob_name=blob_name) 

download_stream = download_client.download_blob()

I have found that SendGrid has the functionality to add files from memory with NodeJS, however I did not find anything like that with Python. SendGrid GitHub

Does anyone know how to do this with Python?

I also found this article on Stack that is more-or-less the same question but not in python and not answered directly. This question here

Answer 1

There is an attachment module under the sendgrid.helpers.mail , you could refer to here: Attachment . Below is my test code, maybe you could have a try.

import sendgrid
import os
from sendgrid.helpers.mail import *
import base64
from sendgrid import SendGridAPIClient
from azure.storage.blob import BlobServiceClient, BlobClient, ContainerClient
from io import BytesIO

message = Mail(
    from_email='from_email@example.com',
    to_emails='to@example.com',
    subject='Sending with Twilio SendGrid is Fun',
    html_content='<strong>and easy to do anywhere, even with Python</strong>')

connect_str ='storage connection string'
blob_service_client = BlobServiceClient.from_connection_string(connect_str)
blobclient=blob_service_client.get_blob_client(container='test',blob='nodejschinesedoc.pdf')
streamdownloader =blobclient.download_blob()
stream = BytesIO()
streamdownloader.download_to_stream(stream)


encoded = base64.b64encode(stream.getvalue()).decode()
attachment = Attachment()
attachment.file_content = FileContent(encoded)
attachment.file_type = FileType('application/pdf')
attachment.file_name = FileName('test_filename.pdf')
attachment.disposition = Disposition('attachment')
attachment.content_id = ContentId('Example Content ID')
message.attachment = attachment
try:
    sendgrid_client = SendGridAPIClient('sendgrid API key')
    response = sendgrid_client.send(message)
    print(response.status_code)
    print(response.body)
    print(response.headers)
except Exception as e:
    print(e.args)