I am trying to loop through an array backwards starting from an index number of 96
.
for (let i = keyToValue2.length[96] - 1; i >= 0; i--) {
console.log(keyToValue2[i])
}
This is my code so far and I can't find any posts about this. Also, this is my first post sorry if I didn't type code correctly.
You don't need to slice the array (which uses additional memory, as it creates a new array) to do that.
What you are describing is a loop that starts at index = 96
until it reaches 0
, decreasing index
one by one.
So you just need to change let i = keyToValue2.length[96] - 1
to let i = 96
.
Here's an example using an array with 32
values and logging them backwards, starting at index 16
. Just used these values because StackOverflow snippets limit the number of log entries:
// This creates a new array with 32 numbers (0 to 31, both included): const array = new Array(32).fill(null).map((_, i) => `Element at index ${ i }.`); // We start iterating at index 16 and go backwards until 0 (both included): for (let i = 16; i >= 0; --i) { console.log(array[i]) }
If you want to make sure the index 96
actually exists in your array, then use let i = Math.min(96, keyToValue2.length - 1
:
// This creates a new array with 32 numbers (0 to 31, both included): const array = new Array(32).fill(null).map((_, i) => `Element at index ${ i }.`); // We start iterating at index 31 (as this array doesn't have 64 elements, it has only 32) // and go backwards until 0 (both included): for (let i = Math.min(64, array.length - 1); i >= 0; --i) { console.log(array[i]) }
Try this,
slice array up to which index you want, then loop it reverse order.
var sliced = keyToValue2.slice(0, 96);
for (let i = sliced.length - 1; i >= 0; i--) {
console.log(keyToValue2[i])
}
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