I have a pandas data frame of the following type;
id | a | b | c | d | e | g
---------------------------
1 | 0 | 1 | 0 | 1 | 1 | 1
2 | 0 | 0 | 0 | 0 | 1 | 0
3 | 0 | 0 | 0 | 0 | 1 | 1
I want to filter rows which has zero for all columns, a
through d
. I am aware that this can be achieved by;
data[data['a']==0 & data['b']==0 & data ['c'] ==0 & data ['d'] ==0]
But is there a quicker way using iloc
or loc
to achieve the same. For example, I tried the following;
data.iloc[:,[1:4]==0]
But it gave me following error message; ValueError: Can only index by location with a [integer, integer slice (START point is INCLUDED, END point is EXCLUDED), listlike of integers, boolean array]
Any alternate feedback/advice, which can replace my original solution is appreciated.thanks
Do you mean:
df[df.iloc[:,1:4].eq(0).all(1)]
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.